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    <p>The explanations above apply to Aggregate Analysis, the idea of taking "an average" over multiple operations. I am not sure how they apply to Bankers-method or the Physicists Methods of Amortized analysis.</p> <p>Now. I am not exactly sure of the correct answer. But it would have to do with the principle condition of the both Physicists+Banker's methods:</p> <p>(Sum of amortized-cost of operations) >= (Sum of actual-cost of operations).</p> <p>The chief difficulty that I face is that given that Amortized-asymptotic costs of operations differ from the normal-asymptotic-cost, I am not sure how to rate the significance of amortized-costs. </p> <p>That is when somebody gives my an amortized-cost, I know its not the same as normal-asymptotic cost What conclusions am I to draw from the amortized-cost then?</p> <p>Since we have the case of some operations being overcharged while other operations are undercharged, one hypothesis could be that quoting amortized-costs of individual operations would be meaningless. </p> <p>For eg: For a fibonacci heap, quoting amortized cost of just Decreasing-Key to be O(1) is meaningless since costs are reduced by "work done by earlier operations in increasing potential of the heap."</p> <p>OR </p> <p>We could have another hypothesis that reasons about the amortized-costs as follows:</p> <ol> <li><p>I know that the expensive operation is going to preceded by MULTIPLE LOW-COST operations. </p></li> <li><p>For the sake of analysis, I am going to overcharge some low-cost operations, SUCH THAT THEIR ASYMPTOTIC-COST DOES NOT CHANGE.</p></li> <li><p>With these increased low-cost operations, I can PROVE THAT EXPENSIVE OPERATION has a SMALLER ASYMPTOTIC COST.</p></li> <li><p>Thus I have improved/decreased the ASYMPTOTIC-BOUND of the cost of n operations.</p></li> </ol> <p>Thus amortized-cost analysis + amortized-cost-bounds are now applicable to only the expensive operations. The cheap operations have the same asymptotic-amortized-cost as their normal-asymptotic-cost.</p>
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