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    <p>There are many many problems with this code (from major ones like not being compilable, so I don't even know how you get the runtime errors), to minor stylistic issues.</p> <p>However, since you talk about variable passing, I will zero in on that piece.</p> <hr> <p>Here's where you call your functions:</p> <pre><code>my @array = &amp;function1(); my $arrayvalue = &amp;function2(); &amp;function1($search); &amp;function2(@array); </code></pre> <p>So, you FIRST call <code>function1</code> with no arguments (which will presumably run incorrectly, as you didn't pass the search string - and resulted in <code>uninitialized value $search in concatenation</code> error you mentioned in the comment), and assign an empty array results into <code>@array</code>.</p> <p>THEN, you call <code>function1</code> <strong>again</strong>, this time correctly (passing $search parameter), but ignore the return value (so <code>@array</code> will remain empty from first call). </p> <p>Same problems for second function.</p> <p>This should have been:</p> <pre><code>my @array = function1($search); my $arrayvalue = function2(@array); </code></pre> <hr> <p>Second big problem is that you are passing along the data as an array to a second function, but inside the function assigning it as a scalar (presumably as if you passed an array reference). </p> <p>Your code:</p> <pre><code># Called via "function2(@array)"; my @array = $_[0]; </code></pre> <p>If you intend to pass an array, you need to process the parameter array as a whole array:</p> <pre><code># Called via "function2(@array)"; my @array = @_; </code></pre> <p>Whereas if you intend to pass-by-reference, as a single array reference parameter (which is more advanced of a technique but stongly recommended over passing an array for a variety of reasons):</p> <pre><code># Called via "function2(\@array)"; # Notice the "\" in front of "@" - this is a "take a reference" operator my $arrayRef = $_[0]; # We only take 1 parameter, the array reference, now my @array = @$arrayRef; # Dereference array ref into an array. # You can also use arrayref directly instead once you learn about data structures </code></pre>
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