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POGet access to an image view from ListFragment
 

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  1. POGet access to an image view from ListFragment
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    <p>I have a ListFragment with its Layout A and for each item on the list I have its layout as well called B. Inside B I have an image view with id "imgVi":</p> <pre><code>&lt;ImageView android:id="@+id/imgVi" android:layout_width="wrap_content" android:layout_height="wrap_content"/&gt; </code></pre> <p>From my ListFragment in the method onCreateView I want to get access to this ImageView for change the image src. How can I do this?. Since this imageView is not in the ListFragment layout, I cant do this:</p> <pre><code>ImageView imgEmp = (ImageView) view.findViewById(R.id.imageViewEmp); imgEmp.setBackgroundResource(R.drawable.ic_tab_emp_selected); </code></pre> <p>But layout B is in layout A. Because its a list with its rows.</p> <p>Any help will be apreciated. I'm new with Android.</p> <p>EDITED: I got it work, just follow this tutorial <a href="http://thinkandroid.wordpress.com/2010/01/11/custom-cursoradapters/" rel="nofollow">http://thinkandroid.wordpress.com/2010/01/11/custom-cursoradapters/</a></p> <pre><code>public class ListClientsCursorAdapter extends SimpleCursorAdapter{ private Context context; private int layout; public ListClientsCursorAdapter(Context context, int layout, Cursor c, String[] from, int[] to, int flags) { super(context, layout, c, from, to, flags); this.context = context; this.layout = layout; } @Override public View newView(Context context, Cursor cursor, ViewGroup parent) { Cursor c = getCursor(); final LayoutInflater inflater = LayoutInflater.from(context); View v = inflater.inflate(layout, parent, false); int nameCol = c.getColumnIndex("name"); String name = c.getString(nombreCol); int telfCol = c.getColumnIndex("telf"); String telf = c.getString(telfCol); /** * Next set the name of the entry. */ TextView name_text = (TextView) v.findViewById(R.id.textViewNombEmp); if (name_text != null) { name_text .setText(name); } TextView telf_text = (TextView) v.findViewById(R.id.textViewTelfEmp); if (telf_text != null) { telf_text.setText(telf); } ImageView imgEmp = (ImageView) v.findViewById(R.id.imageViewEmp); if (imgEmp != null) { imgEmp.setBackgroundResource(R.drawable.ic_tab_emp_selected); } return v; } } </code></pre> <p>And then in my onCreateView of the ListFragment I call:</p> <pre><code>ListClientCursorAdapter notes = new ListClientCursorAdapter(context,R.layout.activity_fil_client, mCursor, from, to, 0); setListAdapter(notes); </code></pre> <p>Instead of SimpleCursorAdapter.</p>
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    1. COI didn't quite understand. So B is the layout for each row of your List. right? it means you have 0 or more (depending on number of items on the list) of these imageviews? If that's the case you should access that imageview inside the adapter not in your onCreateView method!!
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      1. USSaeid Farivar
    2. COyes, thats right. I'll an image view for each row. Can you provide me any example of that?.
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      1. USkiduxa
 

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