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16430238
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2013-05-07T23:27:13.880
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2013-05-08T00:55:26.807
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2013-05-08T00:55:26.807
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1715579
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<p>I'll take a stab at this... You can use Linq to generate all the date ranges at once. It's not exactly the prettiest query, but it works.</p> <pre><code>DateTime start = ... DateTime end = ... var cal = System.Globalization.CultureInfo.CurrentCulture.Calendar; var range = from y in Enumerable.Range(start.Year, end.Year - start.Year + 1) let maxMonth = y < end.Year ? cal.GetMonthsInYear(y) : end.Month let minMonth = y > start.Year ? 1 : start.Month from m in Enumerable.Range(minMonth, maxMonth - minMonth + 1) let isStart = (y == start.Year && m == start.Month) let isEnd = (y == end.Year && m == end.Month) select new { StartDate = isStart ? start : new DateTime(y, m, 1), EndDate = isEnd ? end : new DateTime(y, m, cal.GetDaysInMonth(y, m)), NumberOfMonths = isStart || isEnd ? .5 : 1 }; </code></pre> <p>It iterates over the years from <code>start</code> to <code>end</code>, then iterates over the months in each year, with special handling on the edge cases (<code>isStart</code> and <code>isEnd</code>). This basic algorithm can be encapsulated in a function like this:</p> <pre><code>public class DateTimeRange { Date StartDate { get; set; } Date EndDate { get; set; } float NumberOfMonths { get; set; } } public static IEnumerable<DateTimeRange> SplitByMonths(DateTime start, DateTime end, Calendar cal) { return ( from y in Enumerable.Range(start.Year, end.Year - start.Year + 1) let maxMonth = y < end.Year ? cal.GetMonthsInYear(y) : end.Month let minMonth = y > start.Year ? 1 : start.Month from m in Enumerable.Range(minMonth, maxMonth - minMonth + 1) let isStart = (y == start.Year && m == start.Month) let isEnd = (y == end.Year && m == end.Month) select new DateTimeRange { StartDate = isStart ? start : new DateTime(y, m, 1), EndDate = isEnd ? end : new DateTime(y, m, cal.GetDaysInMonth(y, m)), NumberOfMonths = isStart || isEnd ? .5 : 1 }); } </code></pre>
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