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    <p>In java, using a zero as the most significant digit, it interpreters the number as an octal number. So <code>01234</code> gets converted to:</p> <pre><code>4 + 3 x 8 + 2 x 8^(2) + 1 x 8^(3) = 668 </code></pre> <p>So you are better off with using one of the convert-to-string methods as in the other answers.</p> <p><strong>Edit:</strong> Here is a version without StringBuffer etc.:</p> <pre><code>public String getReversed(int number) { char[] digitArray = String.valueOf(number).toCharArray(); String strNum = ""; for (int i = digitArray.length - 1; i &gt;= 0; i--) { strNum += digitArray[i]; } return strNum; } </code></pre> <p><strong>2nd edit:</strong> Reversing a <code>char</code> array and then create the <code>String</code> after finished reversing, because of a possible creation of number of <code>O(n^2)</code> operations that could be a problem for the garbage collector.</p> <pre><code>public String getReversed(int number) { char[] digitArray = String.valueOf(number).toCharArray(); char[] reversedDigitArray = new char[digitArray.length]; for (int i = 0; i &lt; digitArray.length; i++) { reversedDigitArray[i] = digitArray[digitArray.length - i - 1]; } return new String(reversedDigitArray); } </code></pre> <p><strong>3rd Edit:</strong> Swaps chars with in-place algorithm.</p> <pre><code>public static String getReversed(int number) { char[] digitArray = String.valueOf(number).toCharArray(); int count = digitArray.length - 1; char tmp; for (int i = (count-1) &gt;&gt; 1; i &gt;= 0; --i) { tmp = digitArray[i]; digitArray[i] = digitArray[count - i]; digitArray[count - i] = tmp; } return new String(digitArray); } </code></pre>
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    1. POReverse an integer without losing 0's in input
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    1. USBjørn Bråthen
    1. USBjørn Bråthen
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    1. COIt might be better to simply reverse the char[] in place and then use the String(Char[]) constructor, since as it stands there is the possibility of creating a number of O(N^2) operation with a lot of garbage collection.
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      1. USVarun Madiath
    2. CO@VarunMadiath Is this better?
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    3. COI'd say it is, further improvement would be to sort it in place, but the number of digits in maximum value of int makes the penalty here too small to worry about.
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      1. USVarun Madiath
 

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