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    <p>I might give you some ideas towards the working algorithm.</p> <p>First of all, you need to divide your input <code>String</code> into parts (<code>[String]</code>) according to your <code>find</code> strings. So this function is</p> <pre><code>divideIntoParts :: [String] -&gt; String -&gt; [String] </code></pre> <p>which works something like </p> <pre><code>divideIntoParts find "The House with Mouse is big" </code></pre> <p>gives </p> <pre><code>["The ", "Hou", "se with ", "Mouse", " is big"] </code></pre> <p>So it extracts the parts to replace from the string, but preserves the order of letters by keeping other parts in the same list. The naive implementation might look like this</p> <p><a href="https://gist.github.com/Shekeen/5523749" rel="nofollow">https://gist.github.com/Shekeen/5523749</a></p> <p>Next you'll need a function to scan through this list and replace the parts, which need to be replaced. The signature will be</p> <pre><code>replaceParts :: [String] -&gt; [String] -&gt; [String] -&gt; String </code></pre> <p>which works like</p> <pre><code>replaceParts find repl $ divideIntoParts find "The House with Mouse is big" </code></pre> <p>will be</p> <pre><code>"The Mouse with House is big" </code></pre> <p>So your full <code>replace</code> function will look like</p> <pre><code>replacePatterns :: [String] -&gt; [String] -&gt; String -&gt; String replacePatterns find repl = (replaceParts find repl) . (divideIntoParts find) </code></pre> <p>Also you really need to implement a faster substring search algorithm and consider replacing <code>find</code> and <code>repl</code> with one <code>Data.Map</code></p>
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    1. POHow to replace more than one element at the same time in a String (Haskell)
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    1. USAnton Guryanov
    1. USAnton Guryanov
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    1. POHow to replace more than one element at the same time in a String (Haskell)
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    1. COHow can i write divideIntoParts function without help of Data.List.Split .I am novice so i couldnt get over the "return value" problem.I mean the function returns [String] so i cant do something like-> else [[head text] ++ divideIntoParts find (tail text)]
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    2. COThe main idea is to find the leftmost substring in your input string, which matches a string from `find`. Then you'll get your string divided into three parts: before matched substring, matched substring, after matched substring. Then you do the same recursively, but apply it to the part after matched substring. I'll update my answer with actual code later, but I think you'll get the idea.
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      1. USAnton Guryanov
    3. COyeah i understood the algorithm i thought about it aswell but i couldn't write the function because of the "type match error".The function returns [String] i have to bind the unmatched part together and its String.I have to do String ++ String so how am i going to do that recursively? i'd be very glad if you update your code because i have no idea how to write this algorithm
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