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POhow to use mod in assembly x86
 

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    <p>I have a question on assembly x86 architecture.</p> <pre><code>INCLUDE Irvine32.inc .data day BYTE 0 month BYTE 0 year BYTE 0 a BYTE 0 y BYTE 0 m BYTE 0 count BYTE 0 prompt1 BYTE "enter month: ",0 prompt2 BYTE "enter day: ",0 prompt3 BYTE "enter an year: ",0 prompt4 BYTE " the day of the week is ",0 .code main PROC mov edx, OFFSET prompt1 call writeString mov eax, OFFSET month mov ecx, 19 call readInt call crlf mov edx, OFFSET prompt2 call writeString mov eax, OFFSET day mov ecx, 19 call readInt call crlf mov edx, OFFSET prompt3 call writeString mov eax, OFFSET year mov ecx, 19 call readInt call crlf mov al, 14 sub al, month mov bl, 12 div bl mov a, al mov al, 0 mov ah, year sub ah, a mov y, ah mov ah, 0 mov bh, 12 mul a add bh, a mov ch, 2 sub bh, ch mov m, bh mov bh, 0 mov ch, 0 mov al, 31 mul m mov ah, 12 div ah mov bl, y mov bh, day add bh, y mov cl, y mov ch, 4 div ch add bh, cl mov dl, y mov dh, 4 div dh add bh, cl add bh, al mov al, 0 mov al, 7 // mod 7 div al exit main ENDP END main </code></pre> <p>So I am supposed to do these arithmetic equations:</p> <pre><code>a = (14 - month) / 12 y = year - a m = month + (12 * a) - 2 d = (day + y + y/4 - y/100 + y/400 + (31 * m / 12)) % 7 </code></pre> <p>For the last equation of <code>mod 7</code>, I got an error, "integer overflow", this is due to using <code>bl</code> I think.</p> <p>If I do something like this</p> <pre><code>mov ax, "thing in parenthesis" mov cl, 7 div cl </code></pre> <p>then I would get <code>al</code> is quotient, <code>ah</code> is remainder.</p> <p>But how would I do <code>mod</code> without having to use <code>ax</code> register?</p>
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