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    <p>Starting with the first part of your question, let's see what happens when you use statement:</p> <pre><code>char *somestring = "somestring"; </code></pre> <p>Here,you declare a <code>character pointer</code> <strong>somestring</strong>, the string <code>somestring</code> is stored at some address in the memory and that address is allocated to the pointer <strong>somestring</strong> (Believe me, it's confusing to use the same name for the pointer and the contents of the string it is pointed to, as you have done!!)</p> <p>Now you can refer to that string using this pointer <code>somestring</code>.</p> <p>Now see, how it is different in the following statement, which will produce errors:</p> <pre><code>int *someint = 45 </code></pre> <p>Here you are declaring an integer pointer <code>someint</code>(of type <code>int*</code>) but assigning an integer value (of type <code>int</code>) to it.Not only is there a <code>type</code> mismatch, but it can produce unpredictable behavior as you just have no idea what is already at address 45.I suppose this is what you need:</p> <pre><code> int num=45,*someint=&amp;num; </code></pre> <p>Here the <code>&amp;</code> <strong>address of</strong> operator assigns the address of the variable <code>num</code> to the pointer, and you can dereference it using the <code>*</code> operator as following:</p> <pre><code> printf("The value pointed by the pointer is ",*someint); </code></pre> <p>Note how <strong>*</strong> before <code>someint</code> carries a different meaning in the declaration statement and as an argument to <code>printf()</code>.</p> <p>Coming to the second part of your question, why we use <code>str1</code> in <code>printf()</code> instead of <code>*str1</code>, well, <code>str1</code> signifies the <strong>base address</strong> of the string ,which is nothing but the address of the first character in the array. So going by what I told you about the <strong>*</strong> operator, <code>*str1</code> means the character stored at the base address of the array,ie, the first character of the array.Run the following code and it will be clear:</p> <pre><code>#include&lt;stdio.h&gt; int main(void) { char str1[10]="Davies"; printf("str1 is : %s \n but *str1 is : %c",str1,*str1); } </code></pre> <p><strong>Output</strong> <code>str1 is : Davies</code></p> <pre><code> but *str1 is : D </code></pre>
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