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  1. PO
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    <p>It would be easier to understand your problem if you post the table structure and some sample data. But here are a few suggestions based on your current query that you might be able to use.</p> <p>These queries reduce the number of subqueries that you are using. One of the obvious changes is the difference in the way it gets the list of <code>user_id</code>'s with each group:</p> <pre><code>select user_id from group_user_map where group_id in (2601,119) union all select user_id from group_user_map where group_id in (58,226) union all select user_id from group_user_map where group_id in (1299,525) union all select user_id from group_user_map where group_id in (2524,128); </code></pre> <p>This uses a <code>UNION ALL</code> which will list all of the <code>user_id</code> even if they are duplicated. Once you have this list of <code>user_id</code>'s then you get the <code>count</code> by applying a <code>count(distinct user_id)</code> and use a <code>HAVING</code> clause to find those that have 4 occurrences. </p> <p>First, you could consolidate your current query to the following version in a <code>WHERE</code> clause:</p> <pre><code>select * from users_table where username IN (select user_id from ( select user_id from group_user_map where group_id in (2601,119) union all select user_id from group_user_map where group_id in (58,226) union all select user_id from group_user_map where group_id in (1299,525) union all select user_id from group_user_map where group_id in (2524,128) ) thegroups where user_id not in (select user_id from group_user_map where group_id in (2572)) group by userid having count(distinct userid) = 4); </code></pre> <p>Or you could use the query in the <code>WHERE</code> clause in a subquery that you JOIN to:</p> <pre><code>select ut.* from users_table ut inner join ( select user_id from ( select user_id from group_user_map where group_id in (2601,119) union all select user_id from group_user_map where group_id in (58,226) union all select user_id from group_user_map where group_id in (1299,525) union all select user_id from group_user_map where group_id in (2524,128) ) thegroups where user_id not in (select user_id from group_user_map where group_id in (2572)) group by userid having count(distinct userid) = 4 ) biggergroup on ut.username = biggergroup.user_id; </code></pre>
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    1. POCan Someone Help me Optimize this mysql statement?
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    1. USTaryn
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      1. VTUpMod
    1. CO@SilicaGel : Is AlL UNION Statements fetches data from different databases(tables). If not then please also try to optimize UNIONS and NOT IN clause also can be excluded because that group_id will never come. Thanks.
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      1. USRonak Vyas
 

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