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    <p>The operator += is an addition assignment operator. Like Alya said above, <code>x += x++</code> is equivalent to <code>x = x + x++</code>, which in your case is <code>x = 10 + 10</code>. However, it's a very messy statement and I'll explain why towards the end of this post.</p> <p>Now, you're probably thinking "Why is it 20 and not 21 (10 + 11) since you have the ++?" and that's valid. There's actually a difference between a post-increment and a pre-increment. x++ is the post-increment and will actually evaluate the value of x first and THEN increment x, while ++x is the pre-increment which will increment x and THEN evaluate the value of x.</p> <p>For example, <code>x = 10; System.out.println(x++); System.out.println(x);</code> will print 10 and then print 11 because the first print line prints <code>x</code> and THEN performs the ++ calculation, making <code>x</code> 11 which the next line prints. Conversely, <code>x = 10; System.out.println(++x); System.out.println(x);</code> will print 11 on both print statements.</p> <p>Going back to why I said <code>x += x++;</code> is very messy is because technically the ++ operator isn't performed in this case. <code>x++</code> is technically the same as <code>x=x+1</code> and remembering that x+=y is the same as x = x+y) , the line <code>x += x++;</code> is kind of like saying <code>x = x + (x = x + 1);</code> which is kind of weird looking because you do 2 assignment statements in one and won't actually "work how you want it". Back to your example <code>int x = 10; x += x++;</code> if you print x, you will get 20 even though you could look at it as: x is now the value of x + the value of x, then finally + 1 to it. But unfortunately, that's not how it works.</p> <p>To solve your problem, if you change your code from a post-increment to a pre-increment, then it should work, ie: <code>x+=++x;</code> will print your 11 but I would argue the that's quite unreadable and a bit confusing. <code>x+=x; x++; System.out.println(x);</code> is easier to follow.</p>
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    1. COVery thorough analysis, thank you very much.
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