StackOverflow2013

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Id
16235367
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0
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0
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CreationDate
2013-04-26T11:29:53.403
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LastActivityDate
2014-02-18T06:52:56.340
LastEditDate
2014-02-18T06:52:56.340
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1083921
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1083921
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16235059
PostTypeId
2
Score
5
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LastEditorDisplayName
text
Body
With <pre><code>password.length </code></pre> you can ask for the length of a string. Compare that to your desired limits. With <pre><code>- (BOOL)string:(NSString *)text matches:(NSString *)pattern { NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:nil]; NSArray *matches = [regex matchesInString:text options:0 range:NSMakeRange(0, text.length)]; return matches.count > 0; } </code></pre> you have a method that provides regex to strings (you can also implement this as a category to NSString). The first parameter will be your password, the second will be the pattern. I am not that good with regex, so there might be better solutions but this would be my way <pre><code>NSString *password = @"iS_bhd97zAA!"; NSString *scPattern = @"[a-z]"; NSString *cPattern = @"[A-Z]"; NSString *sPattern = @"[!%&\._;,]"; NSString *nPattern = @"[0-9]"; if (8 <= password.length && password.length <= 15 && [self string:password matches:scPattern] && [self string:password matches:cPattern] && [self string:password matches:sPattern] && [self string:password matches:nPattern]) { NSLog(@"PW is valid"); } </code></pre> Hint The regex for special characters is tricky because you need to escape some of the chars. Mine might be correct, but I am not absolutely sure. There is also a possiblility to do this in only one regex, but this looks scary imo This one <pre><code> (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$ </code></pre> has everything except the special chars, maybe you want to add that yourself :D
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1. POHow to validate the textfield with 8 to 15 characters and with strong password
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1. PTAnswer
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1. USMarc
UserOwnerUserId
1. USMarc
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1. POHow to validate the textfield with 8 to 15 characters and with strong password
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