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    <p>This was is a tricky one. When there is just one element with class='divclass' the previous answer sure is fine. If there were multiple results from grep, then a find() for a single result is not the answer. Pointing out that the result is an ArrayList is correct. Inserting an outer nested .each() loop provides a GPathResult in the closure parameter <em>div</em>. From here the drill down can continue with the expected result.</p> <pre><code>html."**".grep { it.@class == 'divclass' }.each { div -&gt; div.ol.li.each { linkItem -&gt; def link = linkItem.h3.a.@href def address = linkItem.address.text() println "$link: $address\n" }} </code></pre> <p>The behavior of the original code can use a bit more of an explanation as well. When a property is accessed on a List in Groovy, you'll get a new list (same size) with the property of each element in the list. The list found by grep() has just one entry. Then we get one entry for property <em>ol</em>, which is fine. Next we get the result of ol.it for that entry. It is a list of size() == 1 again, but this time with an entry of size() == 2. We could apply the outer loop there and get the same result, if we wanted to:</p> <pre><code>html."**".grep { it.@class == 'divclass' }.ol.li.each { it.each { linkItem -&gt; def link = linkItem.h3.a.@href def address = linkItem.address println "$link: $address\n" }} </code></pre> <p>On any GPathResult representing multiple nodes, we get the concatenation of all text. That is the original result, first for <em>@href</em>, then for <em>address</em>.</p>
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