StackOverflow2013

Note that there are some explanatory texts on larger screens.

plurals

PO
primarykey
Id
16214934
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
0
CommunityOwnedDate
CreationDate
2013-04-25T12:34:55.557
FavoriteCount
0
LastActivityDate
2013-04-25T12:34:55.557
LastEditDate
LastEditorUserId
0
OwnerUserId
1900384
ParentId
16211532
PostTypeId
2
Score
0
ViewCount
0
LastEditorDisplayName
text
Body
<code>I</code> is a 2D or 3D matrix (depends on grayscale or color). <code>I(:)</code> is the vector where all values of the matrix are written in a column, just like they are arranged in the memory; you could do by <a href="http://www.mathworks.de/de/help/matlab/ref/reshape.html" rel="nofollow"><code>reshape</code></a> as well. Please read more about the colon-operator in <a href="http://www.mathworks.de/de/help/matlab/ref/colon.html" rel="nofollow">Matlab documentation</a>, it is an absolut basic concept of Matlab. <code>max</code> gives you the maximum over a vector, i.e. <code>max(I(:))</code> gives you the maximum value over the whole image. It is an unwritten law that the range of an image starts at 0. Therefore you can map the values of the image to <code>[0,1]</code> by dividing it by <code>max(I(:))</code>. In Matlab it is done like that: <code>myMatrix/myScalar</code>. So <code>I/max(I(:))</code> gives you the image with values in <code>[0,1]</code>, what is required for double-images that you want to show with <code>imshow</code>. Please note: (1) You can write <code>imshow(I,[])</code> instead which will show you the image with values stretched to <code>[0,1]</code> (in difference to your version the minimum is mapped to 0 as well). (2) In my view you should map the values of an image for visualization only in exceptional cases like you do. It can give you wrong impression of the image (e.g. a very dark image will be visualized as full contrast image). Try to devide by maximum of the original value range (often 255, 4095 or 65535). Example: <pre><code>img = imread('some12bit.png'); img = double(img); img = img / 4095; % [0,4095] -> [0,1] imshow(img); </code></pre> (3) Without mapping the image to <code>[0,1]</code> all values <code>> 1</code> will be interpreted as <code>1</code>. That's why your image is shown as a white image without mapping it to <code>[0,1]</code> before.
Tags
Title
singulars
PostAcceptedAnswerId
1. This table or related slice is empty.
PostParentId
1. POShowing an image
 singulars
 PostTypePostTypeId
 PTQuestion
PostTypePostTypeId
1. PTAnswer
UserLastEditorUserId
1. This table or related slice is empty.
UserOwnerUserId
1. USmatheburg
plurals
PostLinksPostIdRelatedPostId
1. This table or related slice is empty.
PostLinksRelatedPostIdPostId
1. This table or related slice is empty.
PostsAcceptedAnswerId
1. This table or related slice is empty.
PostsParentIdCreationDate
1. This table or related slice is empty.
VotesPostIdCreationDate
1. This table or related slice is empty.
CommentsPostId
1. This table or related slice is empty.

Querying!

Guidance

A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.