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POHow to insert multiple ID's in one linked table?
 

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  1. POHow to insert multiple ID's in one linked table?
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    <p>I want to insert de EmployeeID and the KnowledgeID in Knowledgedetail. He creates the employee but does nothing in the Knowledgedetail. I'm there now no code, I have tried so many things but i have no idea.<br> As first in Addprofile.php you make the profile and at least you choose yoour knowledge. My question is if a make a profile and choose the knowledge how get i de ID's in knowledgedetail.</p> <p><strong>Table 1<br> Employees</strong>: EmployeeID, Name, Establishment, E-Mail, Phonenumber, Photo, Description<br> <strong>Table 2<br> Knowledge</strong>: KnowledgeID, Knowledge<br> <strong>Table 3<br> Knowledgedetail</strong>: KnowledgedetailID, EmployeeID KnowledgeID </p> <p>EmployeeID out Employees have a relation with EmployeeID out Knowledgedetail and<br> KnowledgeID out Knowledge have a relation with KnowledgeID out Knowledegedetail</p> <p>Addprofile.php</p> <pre><code>&lt;?php include("connection.php"); ?&gt; &lt;!DOCTYPE html&gt; &lt;html&gt; &lt;head&gt; &lt;title&gt;Information System&lt;/title&gt; &lt;link rel="stylesheet" type="text/css" href="css/test.css"&gt; &lt;meta charset ="utf-8"&gt; &lt;link rel='stylesheet' href='http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/smoothness/jquery-ui.css' type='text/css' media='screen' /&gt; &lt;link rel='stylesheet' href='css/ui.multiselect.css' type='text/css' media='screen' /&gt; &lt;script src="../Informatiesysteem/js/jquery.min.js"&gt;&lt;/script&gt; &lt;script type='text/javascript' src='https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js'&gt;&lt;/script&gt; &lt;script type='text/javascript' src='https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.min.js'&gt;&lt;/script&gt; &lt;script type='text/javascript' src='../Informatiesysteem/js/ui.multiselect.js'&gt;&lt;/script&gt; &lt;script type='text/javascript'&gt; jQuery(document).ready(function() { jQuery("#selectitems").multiselect(); }); &lt;/script&gt; &lt;/head&gt; &lt;body&gt; &lt;div id="container"&gt; &lt;div id="logo"&gt;&lt;/div&gt; &lt;div id="header"&gt; &lt;h1&gt;Add Profile&lt;/h1&gt; &lt;/div&gt; &lt;div id="menu"&gt; &lt;/div&gt; &lt;div id="content"&gt; &lt;?php $result = mysql_query("select knowledgeid, knowledge from knowledge"); $items = array(); $selected = array(); while ($row = mysql_fetch_array($result)){ $id [] = $row [ 'knowlegdeid' ]; $items[] = $row[ 'knowledge' ]; } //form processing if (isset($_POST['selectitems'])) { $selected = $_POST['selectitems']; } if (!empty($selected)) : print_r($selected); endif; ?&gt; &lt;form enctype="multipart/form-data" id="my form" method="post" action="Addedprofile.php"&gt; Name: &lt;input type="text" name="name" /&gt;&lt;/br&gt; Establishment: &lt;input type="text" name="establishment"/&gt;&lt;/br&gt; E-Mail: &lt;input type="email" name="email"/&gt;&lt;/br&gt; Phonenumber: &lt;input type="tel" name="phonenumber"/&gt;&lt;/br&gt; Photo: &lt;input type="file" name="photo"/&gt;&lt;/br&gt; Description: &lt;textarea rows="4" cols="50" name="description"&gt;&lt;/textarea&gt;&lt;/br&gt; Knowledge: &lt;select name="selectitems[]" id="selectitems" multiple="multiple" style="width: 450px; height: 180px;"&gt; &lt;?php //first we add the list of selected items if any foreach ($selected as $sel) { ?&gt; &lt;option value="&lt;?php echo $sel; ?&gt;" selected="selected"&gt;&lt;?php echo $id[$sel]; $items[$sel];?&gt;&lt;/option&gt; &lt;?php } ?&gt; &lt;?php foreach ($items as $i =&gt; $v) { //then insert all items, skipping those who were added above if (in_array($d, $i, $selected)) : continue; endif; //skip ?&gt; &lt;option value="&lt;?php echo $d, $i; ?&gt;"&gt;&lt;?php echo $v; ?&gt;&lt;/option&gt; &lt;?php } ?&gt; &lt;/select&gt; &lt;/br&gt;&lt;/br&gt;&lt;/br&gt;&lt;/br&gt; &lt;input type="submit" name="add_profile" value="Add profile" /&gt; &lt;/form&gt; &lt;/div&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>Addedprofile.php</p> <pre><code>&lt;!DOCTYPE html&gt; &lt;html&gt; &lt;meta http-equiv="refresh" content=";URL=Addprofile.php" /&gt; &lt;/html&gt; &lt;?php include ("connection.php"); $Name = $_POST['name']; $Establishment = $_POST['establishment']; $Email = $_POST['email']; $Phonenumber = $_POST['phonenumber']; $Photo = $_POST['photo']; $Description = $_POST['description']; $sql = "INSERT INTO employees ( name, establishment, email, phonenumber, photo, description ) VALUES ('". $Name ."', '". $Establishment ."', '". $Email ."', '". $Phonenumber ."', '". $Photo ."', '". $Description ."')"; $sqldetail = "INSERT INTO knowledgedetail ( employeeid, knowledgeid ) VALUES ......................."; $add = mysql_query($sql); if ($add === false){ echo 'Profile is not created'; } else { echo "Profile created"; } echo '&lt;/br&gt;'; $knowledge = mysql_query($sqldetail); if ($add === false){ echo 'Knowledge is not added'; } else { echo "Knowledge added"; } echo '&lt;/br&gt;'; ?&gt; </code></pre>
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    1. USMMTjoelkerT
    1. USMMTjoelkerT
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      1. POHow to insert multiple ID's in one linked table?
      1. USMarjeta
      1. VTFavorite
    1. COyou forgot your values at the second insert?
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      1. POHow to insert multiple ID's in one linked table?
      1. USNaruto
    2. COI have no idea what it should be, I tried a lot but al didn't work.
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      1. POHow to insert multiple ID's in one linked table?
      1. USMMTjoelkerT
    3. COyou never close the $sqldetail, and you never execute the $sqldetail... Unless you didn't give us all the code..
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      1. POHow to insert multiple ID's in one linked table?
      1. USNaruto
 

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