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    <p>Hope this helps</p> <pre><code> #include&lt;stdio.h&gt; void change(int *c)/*Pointer c now has the first location of the array a[]*/ { *(c+0) = 0;/*assign values to the array by adding step-size to the first array position*/ *(c+1) = 1; *(c+2) = 2; *(c+3) = 3; *(c+4) = 4; } main() { int a[5]={10,20,30,40,50}; /* Declare and Assign an array a[] of size 5.*/ int *b = a; /*Declare and assign a Pointer to the location of the array.*/ change(b); /*pass the pointer(which is now pointing to first position of array) to the change() function.*/ printf("%d,%d,%d,%d,%d,",a[0],a[1],a[2],a[3],a[4]);/*Print the changed value.*/ } </code></pre> <p>Output: 0,1,2,3,4,</p> <p>From Java point of view, Pointers are simply like(not exactly) Object references.</p> <pre><code>Object O; O = New SomeClassName(); </code></pre> <p>Like Object Reference O is pointing to some Actual Object of type SomeClassName, so does pointers in C:</p> <pre><code>int *b; b = &amp;a; </code></pre> <p>Variable b is simply pointing to the address location to a. Taking a deep dive into array concepts:</p> <pre><code>int a[5]; int *b = a; </code></pre> <p>Here we are just saying like <strong>Mr.*b</strong> point to the first location of group <strong>a</strong> i.e. <strong>a[0]</strong>.</p> <p>Now the power pointer in C is that from now on, here after:</p> <pre><code>*b means a[0] *(b+1) means a[1] *(b+2) means a[2] *(b+3) means a[3] *(b+4) means a[4] </code></pre> <p>This means you change in *(b+4), you're changing a[4]. </p>
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    1. COThis is a contrived example that has no explanation attached.
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    2. CO@siride **Now check.**
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    3. CO@KishoreDebnath It's still as useless to a newbie unless you give some explanation.
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