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POwhy does my printf statement pop up simultaneously? and get an infinite loop?
 

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  1. POwhy does my printf statement pop up simultaneously? and get an infinite loop?
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    <p>Why is it that when I start the program, I will start by doing the first printf statement, and then i input, then it simultaneously does two printf statements. Is this what's causing the infinite loop as well? </p> <p>Starting the program </p> <pre><code>Player 1: Choose your symbol: a </code></pre> <p>This part, they both output simultaneously</p> <pre><code>Player 2: Choose your symbol: player1, enter placement: </code></pre> <p>And then I get an infinite loop. Is it due to the simultaneous output? </p> <p>code</p> <pre><code>include &lt;stdio.h&gt; int check(char player); void move(char player); char board[3][3] ; int main(void) { int first; char player1, player2; printf("Player 1: Choose your symbol: \n"); player1 = getchar(); printf("Player 2: Choose your symbol: \n"); player2 = getchar(); int i=0; int win;char turn; while(win == 0) { if((i%2) == 0){ turn = player1; move(player1); win = check(player1); print();} else { turn = player2; move(player2); win = check(player2); print();} i++; } if (i == 8) printf("its a tie"); else printf("the winner is %c", turn); return 0; } /*printing the board that takes in a placement int*/ void print(void) { int r; printf("\n"); for (r = 0; r &lt; 3; r++){ printf(" %c | %c | %c \n" , board[r][0], board[r][2], board[r][3]); if (r != 2) printf("___________\n"); } printf("\n"); return; } /*check to see if someone won*/ int check(char player) { int r, c; for ( r = 0 ; r &lt;3 ; r++) { if ((board[r][0] == player) &amp;&amp; (board[r][1] == player) &amp;&amp; (board[r][2] == player)) return 1; } for ( c = 0 ; c &lt;3 ; c++) { if ((board[0][c] == player) &amp;&amp; (board[1][c] == player) &amp;&amp; (board[2][c] == player)) return 1; } if((board[0][0] == player) &amp;&amp; (board[1][1] == player) &amp;&amp; (board[2][2] == player)) return 1; if((board[0][2] == player) &amp;&amp; (board[1][1] == player) &amp;&amp; (board[2][0] == player)) return 1; return 0; } void move(char player) { int place; printf("player1, enter placement: \n"); scanf("%d", &amp;place); if (place == 1) board[0][0] = player; else if (place == 2) board[0][1] = player; else if (place == 3) board[0][2] = player; else if (place == 4) board[1][0] = player; else if (place == 5) board[1][1] = player; else if (place == 6) board[1][2] = player; else if (place == 7) board[2][0] = player; else if (place == 8) board[2][1] = player; else if (place == 9) board[2][2] = player; } </code></pre>
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    1. USmonkey doodle
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    1. COYou are not initializing the variable `win` ? Still it works?
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      1. POwhy does my printf statement pop up simultaneously? and get an infinite loop?
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    2. CO@Shiju OP got lucky.
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      1. POwhy does my printf statement pop up simultaneously? and get an infinite loop?
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