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POHow to format complex number output with negative or zero values
 

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  1. POHow to format complex number output with negative or zero values
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    <p>Please I need to write a program that takes two complex numbers from the user and output their difference. Complex numbers are those numbers in the form of a+bi, where a and b are real numbers known as the real and imaginary parts respectively. Thus, the difference between two complex numbers a1+b1i and a2+b2i is (a1-a2)+(b1-b2)i. I wrote the codes as</p> <pre><code>#include&lt;iostream&gt; using namespace std; class cmp { private: double re, im; public: cmp(double a, double b) {re=a; im=b;} friend cmp operator+(cmp&amp;, cmp&amp;); void show() {cout&lt;&lt;re&lt;&lt;" + "&lt;&lt;im&lt;&lt;"i"&lt;&lt;endl;} }; cmp operator+(cmp&amp; p, cmp&amp; q) {return cmp (p.re-q.re, p.im-q.im);} main() { double m1, n1, m2, n2; cout&lt;&lt;"Give two complex numbers: "; cin&gt;&gt;m1&gt;&gt;n1; cout&lt;&lt;endl; cout&lt;&lt;"Give another two complex numbers: "; cin&gt;&gt;m2&gt;&gt;n2; cout&lt;&lt;endl; cmp c1(m1,n1); cmp c2(m2,n2); cmp c3=c1+c2; c3.show(); system("PAUSE"); } </code></pre> <p>However, when you look at the difference (a1-a2)+(b1-b2)i, if</p> <ol> <li><p>b2>b1, then the imaginary part in the difference will be negative. For example (10.5+2i)-(5+4i)=5.5-2i. But, the program can't display that and display 5+-2i instead. How can my program be in usual maths format?</p></li> <li><p>a1=a2 and/or b1=b2, 0 is/are displayed in the program unlike the usual format in maths. For example, mathematically, (4+7i)-(4+5i)=(4-4)+(7-5)i=2i. But this program will display 0+2i instead. How can I solve this problem too?</p></li> </ol> <p>Please I need a clue on how to overcome these. Thanks.</p>
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    1. COWelcome to SO! Your question is not clear, as your title mentions "overloading", while your body text asks a different or much more vague question. Be more specific - how does your question relate to operator overloading? What is the actual question you are trying to resolve?
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    2. COI think you can see how I overload '+' operator in the program and my questions are stated at the end of each of those two list I mentioned.
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    3. COIndeed, there is code depicting an overloaded operator. However, the questions are worded in a way that is not clear and is difficult to understand what you are trying to accomplish. Please consider revising in a way that clarifies or simplifies the problem at hand.
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