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POPrototypical inheritance - writing up
 

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    <p>So I have these 2 examples, from javascript.info:</p> <p>Example 1:</p> <pre><code>var animal = { eat: function() { alert( "I'm full" ) this.full = true } } var rabbit = { jump: function() { /* something */ } } rabbit.__proto__ = animal rabbit.eat() </code></pre> <p>Example 2:</p> <pre><code>function Hamster() { } Hamster.prototype = { food: [], found: function(something) { this.food.push(something) } } // Create two speedy and lazy hamsters, then feed the first one speedy = new Hamster() lazy = new Hamster() speedy.found("apple") speedy.found("orange") alert(speedy.food.length) // 2 alert(lazy.food.length) // 2 (!??) </code></pre> <p>Start from Example 2: when the code reaches <code>speedy.found</code>, it finds no <code>found</code> property in <code>speedy</code>, and so it climbs up to the prototype and changes it there. That's why <code>food.length</code> is equal for both hamsters, in other words they have the same stomach.<br><br> From this I understand, that when writing up and adding a new property which doesn't exist, the interpreter will go up the prototype chain until it finds the property, and THEN change it.</p> <p>BUT in Example 1 something else happens:<br> we run <code>rabbit.eat</code>, which changes <code>rabbit.full</code>. <code>full</code> property is nowhere to be found, so it should go up the prototype chain to (to object??), and well, I'm not sure what happens here. In this example the property <code>full</code> of <code>rabbit</code> is created and changed, while in the first example it goes up the prototype chain because it cannot find the property.</p> <p>I'm confused and cannot see why this happens.</p>
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    1. COA hint: rabbit.__proto__ !== rabbit.prototype. See http://dailyjs.com/2012/11/26/js101-proto/ for clarification.
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