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2013-04-12T08:52:06.397
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This question was quite interesting. The problem is solved using an aggregate query. SQL Fiddle: <a href="http://www.sqlfiddle.com/#!3/29256/1/0" rel="nofollow">http://www.sqlfiddle.com/#!3/29256/1/0</a> <pre><code>select d.[Client], c.[Account], max([Paid])as 'PAID', d.[Date] from Customer c, Data d where d.[Client] = c.[Client] group by d.[Client],c.[Account],d.[Date]; </code></pre> Produces the Results: <pre><code>CLIENT ACCOUNT PAID DATE 1 Stack 123 January, 01 2013 00:00:00+0000 1 Stack 234 January, 02 2013 00:00:00+0000 1 Stack 33 January, 03 2013 00:00:00+0000 2 Over 674 January, 04 2013 00:00:00+0000 2 Over 2424 January, 05 2013 00:00:00+0000 2 Over 4545 January, 06 2013 00:00:00+0000 3 Flow 22 January, 07 2013 00:00:00+0000 3 Flow 3456 January, 08 2013 00:00:00+0000 3 Flow 445 January, 09 2013 00:00:00+0000 </code></pre> If we had the situation where a Client Could have Many Accounts and we wanted to find the Client-Account with the largest Amount Paid for a specific date we would have to do something more complicated: <pre><code>select * from Customer c2, Data d2, ( select d.[Client], max([Paid])as 'PAID', d.[Date] from Customer c, Data d where d.[Client] = c.[Client] group by d.[Client],d.[Date] ) subQ where c2.[client] = d2.[client] and c2.[client] = subQ.[client] and d2.[Paid] = subQ.[Paid] and d2.[Date] = subQ.[Date]; </code></pre> As you cannot add additional columns to a query that are not part of the group by - see: <a href="http://technicalsmile.blogspot.gr/2011/04/column-is-invalid-in-select-list.html" rel="nofollow">http://technicalsmile.blogspot.gr/2011/04/column-is-invalid-in-select-list.html</a>
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1. POMax payment by client showing account SQL
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1. USMenelaos Bakopoulos
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1. USMenelaos Bakopoulos
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