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POInserting e-mail address in MySQL using PHP
 

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  1. POInserting e-mail address in MySQL using PHP
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    <p>The last few hours I've spent in struggling with a quite ridiculous error. Simply what I'm making a registration form. User need to enter a e-mail and the mail will be stored in a mysql table. (I have to warn you - please disregard the security issue, the whole thing is just a exercise). But I constantly get the following error from the sql:</p> <blockquote> <p>You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@gmail.com,blqh2@gmail.com,1)' at line 1</p> </blockquote> <p>The html is as follows:</p> <pre><code> &lt;form method="post" action="createnew.php"&gt; &lt;label &gt;user name&lt;/label&gt; &lt;input name="login_id"&gt;&lt;/br&gt; &lt;label&gt;password&lt;/label&gt; &lt;input name="password" password&gt;&lt;/br&gt; ...some more stuff... &lt;label&gt;Privet e-mail&lt;/label&gt; &lt;input name="prv_email"&gt;&lt;/br&gt; &lt;label&gt;Public e-mail&lt;/label&gt; &lt;input name="pub_email"&gt;&lt;/br&gt; &lt;label&gt;Are you a reseller&lt;/label&gt; &lt;input type="checkbox" name="reseller"&gt;&lt;/br&gt; &lt;input type="submit"&gt; &lt;/form&gt; </code></pre> <p>Then comes the PHP:</p> <pre><code>$login_id=$_POST['login_id']; $password=$_POST['password']; ...some more stuff... $pub_email=$_POST['pub_email']; echo $prv_email; echo $pub_email; if (array_key_exists('reseller',$_POST)) { $reseller=1; } else { $reseller=0; } $sql="INSERT INTO users". "(login_id,password,usr_phone,region,prv_email,pub_email,reseller)". "VALUES". "($login_id,$password,$usr_phone,$region,$prv_email,$pub_email,$reseller)" </code></pre> <p>And finally the MySQL formatting for the mail field(practically they prv_email and pub_email are with the same formatting)</p> <pre><code> Field | Type | Collation ----------|--------------|------------------- pub_email | varchar(255) | utf8_general_ci </code></pre> <p>I did try a lot off stuff but nothing seems to work. It always crushes at @. and one more thing - I'm running this who code on localhost(using WAMP), not sure if this have anything to deal with the problem. Please let me know if you need any other information and thanks a lot.</p>
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    1. COhttp://dev.mysql.com/doc/refman/5.1/en/string-literals.html
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      1. USCBroe
    2. COdo a `echo $sql;die();` after the $sql line. Then post that here.
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      1. USBlenderer
    3. CORead more about the `@` and why your getting this error: http://stackoverflow.com/questions/1009954/mysql-variable-vs-variable-whats-the-difference
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      1. USSamuel Cook
 

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