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POAwk/Perl convert textfile to csv with sensible format
 

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  1. POAwk/Perl convert textfile to csv with sensible format
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    <p>I have a historical autogenerated logfile with the following format that I would like to convert to a csv file prior to uploading to a database</p> <pre><code>-------------------------------------- Thu Jul 8 09:34:12 BST 2010 BLUE Head 1 Duration = 20 s Activity = 14.9 MBq Sensitivity = 312 cps/MBq -------------------------------------- Thu Jul 8 09:34:55 BST 2010 BLUE Head 1 Duration = 20 s Activity = 14.9 MBq Sensitivity = 318 cps/MBq -------------------------------------- Thu Jul 8 10:13:39 BST 2010 RED Head 1 Duration = 20 s Activity = 14.9 MBq Sensitivity = 307 cps/MBq -------------------------------------- Thu Jul 8 10:14:10 BST 2010 RED Head 1 Duration = 20 s Activity = 14.9 MBq Sensitivity = 305 cps/MBq -------------------------------------- Mon Jul 19 10:11:18 BST 2010 BLUE Head 1 Duration = 20 s Activity = 12.4 MBq Sensitivity = 326 cps/MBq -------------------------------------- Mon Jul 19 10:12:09 BST 2010 BLUE Head 1 Duration = 20 s Activity = 12.4 MBq Sensitivity = 333 cps/MBq -------------------------------------- Mon Jul 19 10:13:57 BST 2010 RED Head 1 Duration = 20 s Activity = 12.4 MBq Sensitivity = 338 cps/MBq -------------------------------------- Mon Jul 19 10:14:45 BST 2010 RED Head 1 Duration = 20 s Activity = 12.4 MBq Sensitivity = 340 cps/MBq -------------------------------------- </code></pre> <p>I would like to convert the logfile to the following format</p> <pre><code>Date,Camera,Head,Duration,Activity 08/07/10,BLUE,1,20,14.9 08/07/10,BLUE,1,20,14.9 08/07/10,RED,1,20,14.9 08/07/10,RED,1,20,14.9 </code></pre> <p>I have used awk to get me close to what I wish </p> <pre><code>awk 'BEGIN {print "Date,Camera,Head,Duration,Activity";RS = "--------------------------------------"; FS="\n";}; {OFS=",";split($3, a, " ");split($4,b, " "); split($5,c," ");print $2,a[1],a[3],b[3],c[3]}' sensitivity.txt &gt; sensitivity.csv </code></pre> <p>which gives me</p> <pre><code>Date,Camera,Head,Duration,Activity ,,,, Thu Jul 8 09:34:12 BST 2010,BLUE,1,20,14.9 Thu Jul 8 09:34:55 BST 2010,BLUE,1,20,14.9 Thu Jul 8 10:13:39 BST 2010,RED,1,20,14.9 Thu Jul 8 10:14:10 BST 2010,RED,1,20,14.9 </code></pre> <p>How can I</p> <p>(a) get rid of the 4 output field separators in line 4 (b) Convert the date format from Thu Jul 8 09:34:12 BST 2010 to DD/MM/YY (Can I do this in pure awk or by piping to perl)</p>
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    1. COFor the date conversion, look at the first answer here http://stackoverflow.com/questions/2121896/converting-dates-in-awk
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    2. COAnd for the useless commas, just check the values of $2, a, b, c, etc... (if ($2) { print ... })
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    3. COI don't think I've seen anyone ask to convert 4-digit years to 2-digit years in their dates since 2000 rolled along. Seriously consider using a YYYYMMDD date format so you can distinguish 1999 from 2099 and trivially sort your data by date.
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