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    <p>A nice thing about Javascript is that its semantics is formally and as unambiguously as possible defined in the standard. Specifically, <a href="http://es5.github.io/#x15.4" rel="nofollow">section 15.4</a> states that:</p> <blockquote> <p>The value of the length property is numerically greater than the name of every property whose name is an array index; whenever a property of an Array object is created or changed, other properties are adjusted as necessary to maintain this invariant. </p> </blockquote> <p>In other words, everytime you change an array, its <code>length</code> is adjusted, however, it's only guaranteed to be greater than <code>max(indexes)</code>, and not necessarily equal to <code>max(indexes)+1</code>. For example, the <a href="http://es5.github.io/#x15.4.4.6" rel="nofollow">pop method</a> always removes the <code>length-1</code>'th element and decrements <code>length</code> by one, no matter how many elements an array actually contains.</p> <p>Also do note that most array methods are generic and don't "know" anything about arrays specifically. They can manipulate arbitrary objects, and if such an object happens to have a property named <code>length</code>, it will be adjusted according to the above rule. Consider:</p> <pre><code>foo = { length: 100, 99: 'hi' } alert([].pop.apply(foo)) // hi alert(foo.length) // 99 alert([].pop.apply(foo)) // undefined alert(foo.length) // 98 </code></pre> <p>That is, in the context of your question it's irrelevant how exactly arrays are represented - <code>pop</code> and friends don't use this information.</p>
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    1. PODoes Array.pop() mess array's length?
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    1. COI've been passing this fiddle around to demonstrate when Array.length is unreliable, in addition to your example. http://jsfiddle.net/6WrkT/1/
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