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POScrapy request+response+download time
 

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    <p><strong>UPD</strong>: Not close question because I think my way is not so clear as should be</p> <p>Is it possible to get current request + response + download time for saving it to Item?</p> <p>In "plain" python I do</p> <pre><code>start_time = time() urllib2.urlopen('http://example.com').read() time() - start_time </code></pre> <p>But how i can do this with Scrapy?</p> <p><strong>UPD</strong>:</p> <p>Solution enought for me but I'm not sure of quality of results. If you have many connections with timeout errors <code>Download time</code> may be wrong (even DOWNLOAD_TIMEOUT * 3)</p> <p>For </p> <p>settings.py</p> <pre><code>DOWNLOADER_MIDDLEWARES = { 'myscraper.middlewares.DownloadTimer': 0, } </code></pre> <p>middlewares.py</p> <pre><code>from time import time from scrapy.http import Response class DownloadTimer(object): def process_request(self, request, spider): request.meta['__start_time'] = time() # this not block middlewares which are has greater number then this return None def process_response(self, request, response, spider): request.meta['__end_time'] = time() return response # return response coz we should def process_exception(self, request, exception, spider): request.meta['__end_time'] = time() return Response( url=request.url, status=110, request=request) </code></pre> <p>inside spider.py in <code>def parse(...</code></p> <pre><code>log.msg('Download time: %.2f - %.2f = %.2f' % ( response.meta['__end_time'], response.meta['__start_time'], response.meta['__end_time'] - response.meta['__start_time'] ), level=log.DEBUG) </code></pre>
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