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POHow to use pyramid.response.FileIter
 

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    <p>I have the following view code that attempts to "stream" a zipfile to the client for download:</p> <pre><code>import os import zipfile import tempfile from pyramid.response import FileIter def zipper(request): _temp_path = request.registry.settings['_temp'] tmpfile = tempfile.NamedTemporaryFile('w', dir=_temp_path, delete=True) tmpfile_path = tmpfile.name ## creating zipfile and adding files z = zipfile.ZipFile(tmpfile_path, "w") z.write('somefile1.txt') z.write('somefile2.txt') z.close() ## renaming the zipfile new_zip_path = _temp_path + '/somefilegroup.zip' os.rename(tmpfile_path, new_zip_path) ## re-opening the zipfile with new name z = zipfile.ZipFile(new_zip_path, 'r') response = FileIter(z.fp) return response </code></pre> <p>However, this is the Response I get in the browser:</p> <p><strong><code>Could not convert return value of the view callable function newsite.static.zipper into a response object. The value returned was .</code></strong></p> <p>I suppose I am not using FileIter correctly.</p> <hr> <h1>UPDATE:</h1> <p>Since updating with Michael Merickel's suggestions, the FileIter function is working correctly. However, still lingering is a MIME type error that appears on the client (browser): <code>Resource interpreted as Document but transferred with MIME type application/zip: "http://newsite.local:6543/zipper?data=%7B%22ids%22%3A%5B6%2C7%5D%7D"</code></p> <p>To better illustrate the issue, I have included a tiny <code>.py</code> and <code>.pt</code> file on Github: <strong><a href="https://github.com/thapar/zipper-fix" rel="nofollow">https://github.com/thapar/zipper-fix</a></strong></p>
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