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PO
 

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    <p>You appear to have a class with a lot of attributes and no easy way of setting them all. You have now run in to a problem where you need a class with an additional attribute but you have to deal with that mess of a base class.</p> <p>I suggest that, instead of creating a subclass and casting, you create a wrapper class around the ugly one:</p> <pre><code>public class BigDumbClass { // A lot of attributes // No Constructor // No init method } public class Wrapper { private BigDumbClass base; private boolean selected; public Wrapper(BigDumbClass base) { this.base = base; this.selected = false; } //getters and setters } </code></pre> <p>Now when you have to create that new list you can wrap everything in the old list</p> <pre><code>List&lt;BigDumbClass&gt; oldList = someData(); List&lt;Wrapper&gt; wraps = aNewList(); for (BigDumbClass bigDumb : oldList) { Wrapper wrap = new Wrapper(bigDumb); if (someCondition()) { wrap.setSelected(true); } wraps.add(wrap); } </code></pre> <p>Ideally, BigDumbClass would implement an interface that Wrapper could also implement, allowing the wrapper to defer all of the calls to the instance it has wrapped. </p> <pre><code>public class BigDumbClass implements SharedInterface { // All the stuff outlined above } public class Wrapper implements SharedInterface { // All the stuff outlined above // Methods defined in SharedInterface public void doSomething() { base.doSomething(); } } </code></pre> <p>Otherwise, you can provide a getter to the instance and access it directly.</p> <pre><code>BigDumbClass base = wrapper.getBase(); base.doSomething(); </code></pre>
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    1. POjava, initialize SubClass from SuperClass
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    1. USJake Greene
    1. USJake Greene
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    1. COJust because you have a reference for a super class does not mean you are pointing to a super class. 'Base baseRef' may be pointing to a SubClass1, so 'SubClass2 subRef = (SubClass2)baseRef' is not a valid cast.
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