StackOverflow2013

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15735067
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2013-03-31T22:01:16.630
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2013-03-31T22:01:16.630
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319878
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15734866
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2
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text
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I think your code could use <a href="http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Class.html#getResourceAsStream%28java.lang.String%29" rel="nofollow">Class.getResourceAsStream()</a> instead (<code>/resources/log.ascii</code> needs to be packaged in the jar, or somewhere else on the classpath). <pre><code>private static String retrieveSelectedWorkspace() throws FileNotFoundException { InputStream in = Gui.class.getResourceAsStream("/resources/log.ascii"); Scanner scanner = new Scanner(in); while(scanner.hasNextLine()) return scanner.nextLine().toString(); return null; } </code></pre> But as to your actual question, you can definitely grab a folder resource from a jar, as long as that folder is packed inside the jar. Test.java: <pre><code>class Test { public static void main(String[] args) { System.out.println(Test.class.getResource("/text.txt")); System.out.println(Test.class.getResource("/folder")); } } </code></pre> Command line. Create a file and a folder. Then try both running the code from a <code>.class</code> file and running the code from a <code>.jar</code> file. <pre><code>C:\Temp>echo text > text.txt C:\Temp>md folder C:\Temp>javac Test.java C:\Temp>java Test file:/C:/Temp/text.txt file:/C:/Temp/folder </code></pre> Create the jar: <pre><code>C:\Temp>jar cvf test.jar Test.class text.txt folder added manifest adding: Test.class(in = 530) (out= 347)(deflated 34%) adding: text.txt(in = 7) (out= 9)(deflated -28%) adding: folder/(in = 0) (out= 0)(stored 0%) </code></pre> Run from the jar: <pre><code>C:\Temp>java -classpath test.jar Test jar:file:/C:/Temp/test.jar!/text.txt jar:file:/C:/Temp/test.jar!/folder </code></pre>
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1. POGetting the path of an inner package of a jar
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1. PTAnswer
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1. USPaul Grime
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1. POGetting the path of an inner package of a jar
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