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POHow to set db adapter to Validator NoRecordExists and use it in controller?
 

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  1. POHow to set db adapter to Validator NoRecordExists and use it in controller?
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    <p>I recently started learning ZF2 and hope someone can help me with this.</p> <p>I am working my way through Rob Allen's Zend Framework 2 Tutorial (many thanks to @rob-allen).</p> <p>Also I use a solution of @AlloVince and @Maciej <a href="/questions/13818525" title="example">How to set db adapter to Validator RecordExists in Zend Framework 2</a> (many thanks to both authors for it) and I confused because didn't to use this solution in <strong>editAction</strong>.</p> <p>I see <code>Fatal error: Call to a member function get() on a non-object</code> in <code>'adapter' =&gt; $this-&gt;getServiceLocator()-&gt;get('Zend\Db\Adapter\Adapter')</code>.</p> <p>1) In the Module.php added</p> <blockquote> <pre><code>public function getServiceConfig() { return array( 'invokables' =&gt; array( 'RegionModel' =&gt; 'FcLibraries\Model\Region', //&lt;-- added it ), 'factories' =&gt; array( 'FcLibraries\Model\RegionTable' =&gt; function ($sm) { $dbAdapter = $sm-&gt;get('Zend\Db\Adapter\Adapter'); $table = new RegionTable($dbAdapter); return $table; }, ), ); } </code></pre> </blockquote> <p>2) In the Region.php added</p> <blockquote> <pre><code>/** * @var */ protected $serviceLocator; /** * @param \Zend\ServiceManager\ServiceLocatorInterface $serviceLocator * @return Library */ public function setServiceLocator(ServiceLocatorInterface $serviceLocator) { $this-&gt;serviceLocator = $serviceLocator; return $this; } /** * @return \Zend\ServiceManager\ServiceLocatorInterface */ public function getServiceLocator() { return $this-&gt;serviceLocator; } </code></pre> </blockquote> <p>and</p> <blockquote> <pre><code> $inputFilter-&gt;add($factory-&gt;createInput(array( 'name' =&gt; 'name', 'required' =&gt; true, 'filters' =&gt; $this-&gt;_filters, 'validators' =&gt; array( array( 'name' =&gt; 'StringLength', 'options' =&gt; array( 'encoding' =&gt; 'UTF-8', 'min' =&gt; 1, 'max' =&gt; 30, ), ), array( 'name' =&gt; 'Db\NoRecordExists', 'options' =&gt; array( 'table' =&gt; $this-&gt;table, 'field' =&gt; 'name', //'exclude' =&gt; array( // 'field' =&gt; 'id', // 'value' =&gt; $this-&gt;id //), 'adapter' =&gt; $this-&gt;getServiceLocator()-&gt;get('Zend\Db\Adapter\Adapter'), ), ), ), ))); </code></pre> </blockquote> <p>3) In the RegionController.php in addAction using</p> <blockquote> <p>$model = $this->getServiceLocator()->get('RegionModel');</p> </blockquote> <p>instead of <code>$model = new Region();</code>.</p> <p>This works fine for addAction, But I can not understand how I should use it in editAction.</p> <p>My</p> <blockquote> <pre><code>public function editAction() { $id = (int)$this-&gt;params()-&gt;fromRoute('id', 0); if (!$id) { return $this-&gt;redirect()-&gt;toRoute('zfcadmin/region', array( 'action' =&gt; 'add' )); } $data = $this-&gt;getRegionTable()-&gt;get($id); $form = new RegionForm(); $form-&gt;bind($data); $form-&gt;get('submitBtn')-&gt;setAttribute('value', 'Save'); $request = $this-&gt;getRequest(); if ($request-&gt;isPost()) { $form-&gt;setInputFilter($data-&gt;getInputFilter()); $form-&gt;setData($request-&gt;getPost()); if ($form-&gt;isValid()) { $this-&gt;getRegionTable()-&gt;save($form-&gt;getData()); return $this-&gt;redirect()-&gt;toRoute('zfcadmin/regions'); } } return array( 'id' =&gt; $id, 'form' =&gt; $form, ); } </code></pre> </blockquote> <p>My RegionTable has the following code:</p> <blockquote> <pre><code>/** * @param \Zend\Db\Adapter\Adapter $adapter */ public function __construct(Adapter $adapter) { $this-&gt;adapter = $adapter; $this-&gt;resultSetPrototype = new ResultSet(); $this-&gt;resultSetPrototype-&gt;setArrayObjectPrototype(new Region()); $this-&gt;initialize(); } public function get($id) { $id = (int)$id; $rowSet = $this-&gt;select(array('id' =&gt; $id)); $row = $rowSet-&gt;current(); if (!$row) { throw new \Exception("Could not find row $id"); } return $row; } </code></pre> </blockquote> <p>Many thanks to all who will answer my question.</p> <p>Best regards, Ruslan.</p>
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