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POWhat is '-1.#IND'?
 

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  1. POWhat is '-1.#IND'?
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    <p>I have some code that will allow me to draw a crescent moon shape, and have extracted the values to excel to be drawn. However in place of some numbers, there is <code>-1.#IND</code> in place. Firstly if anyone could explain what this means, as Google came back with 0 links. And secondly if there is anyway to stop it from occurring.</p> <p>There is a brief analogy of my code. I have lots more code besides this, however that is just calculating angles.</p> <pre><code>for(int j=0; j&lt;=n; j++)//calculation for angles and output displayed to user { Xnew2 = -j*(Y+R1)/n; //calculate x coordinate Ynew2 = Y*(pow(1-(pow((Xnew2/X),2)),0.5)); if(abs(Ynew2) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew2&lt;&lt;", "&lt;&lt;Ynew2&lt;&lt;")"&lt;&lt;endl; } </code></pre> <p>MORE INFO</p> <p>I'm now having the problem with this code. </p> <pre><code>for(int i=0; i&lt;=n; i++) //calculation for angles and output displayed to user { Xnew = -i*(Y+R1)/n; //calculate x coordinate Ynew = pow((((Y+R1)*(Y+R1)) - (Xnew*Xnew)), 0.5); //calculate y coordinate </code></pre> <p>AND </p> <pre><code>for(int j=0; j&lt;=n; j++)//calculation for angles and output displayed to user { Xnew2 = -j*(Y+R1)/((n)+((0.00001)*(n==0))); //calculate x coordinate Ynew2 = Y*(pow(abs(1-(pow((Xnew2/X),2))),0.5)); if(abs(Ynew2) &lt;= R1) cout&lt;&lt;"\n("&lt;&lt;Xnew2&lt;&lt;", "&lt;&lt;Ynew2&lt;&lt;")"&lt;&lt;endl; </code></pre> <p>I am having the problem drawing the crescent moon that I cannot get the two circles to have the same starting point? If this makes sense, I am trying to get two parts of circles to draw a crescent moon as such that they have the same start and end points. The only user input I have to work by is the radius and chosen center point. </p> <p>If anyone has any suggestions on how to do this, it would be great, currently all I am getting more a 'half doughnut' shape, due to the circles not being connected. </p>
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    1. USRory Duncan
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      1. USMysticial
    2. CO@Mysticial Does it stand for -1 times an indeterminate number? Because it could multiple things instead of just -∞... Like -1/0
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      1. USAlbert Renshaw
    3. COAre you taking square-roots to draw your crescent shape? Can we see the formula? Perhaps you are taking the sqrt of a negative number?
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      1. USAlbert Renshaw
 

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