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PO
 

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  1. PO
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    <p>First problem:</p> <p>If your for loop is written such that it does not go over the length of the linked list:</p> <p><code>for (int i = 0; i &lt; length(); i++) {</code></p> <p>Then why do you need this?</p> <pre><code> if (node.getNext().getNext() != null) { node= node.getNext(); } </code></pre> <p>In particular, this code might mean that a node just before the end is evaluated twice, because the node beyond it is <code>null</code>. It is not necessarily making your algorithm wrong, but it smells bad and I don't like it.</p> <p>Second problem:</p> <pre><code> for (int j = 0; j &lt; i; j++) { if (node.getInfo().equals(node.getNext().getInfo())) { isDistinct = false; } } </code></pre> <p>This is a faulty way to calculate duplicates because you do not store and advance the position of the second node you are comparing against. Try something like</p> <pre><code> Node node2 = firstNode(); //idk what method gets the first node :) for (int j = 0; j &lt; i; j++) { if (node.getInfo().equals(node2.getInfo())) { isDistinct = false; break; //optimization, stop as soon as we find a duplicate } node2 = node2.GetNext(); } </code></pre> <p>Finally, <strong>whenever faced with code that does not work, attach a debugger, step through it and notice when the code does not do what you expect it to.</strong> This will solve all logic errors quickly with just a small amount of observation. Even if you don't have access to the debugger, you can use <code>print</code> statements to print the value of various variables and when certain code branches execute and compare to what you expected would happen.</p>
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    1. POHow to count how many different nodes are in my linkedlist?
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    1. USPatashu
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    1. COHe's using a double for loop to compare every element against every other element.
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      1. UScorsiKa
    2. CO@corsiKa He only checks against nodes earlier in the list than the current node, so that you count the first instance of a duplicated node correctly and skip all the others. Plus, it was not working because it did not have a second node that it advanced through the list, it would just compare the node against its next node over and over and over `i` times.
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    3. CO@Patashu so you suggest me to add another node for my j loop ?
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      1. USpharaon450
 

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