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    <p>It's iOS 6 now, things might have changed. TheSquad's answer don't work for me until I managed to add one more line <code>view2.layer.masksToBounds = NO;</code>, otherwise shadow doesn't show. Although documentation says <code>masksToBounds</code> is NO by default, my code shows the opposite. </p> <p>Here is how I make a rounded corner button with shadow, which is among the most commonly used code snippet in my app. </p> <pre><code>button.layer.masksToBounds = YES; button.layer.cornerRadius = 10.0f; view.layer.masksToBounds = NO; // critical to add this line view.layer.cornerRadius = 10.0f; view.layer.shadowOpacity = 1.0f; // set shadow path to prevent horrible performance view.layer.shadowPath = [UIBezierPath bezierPathWithRoundedRect:_button.bounds cornerRadius:10.0f].CGPath; [view addSubview:button]; </code></pre> <p><strong>EDIT</strong></p> <p>If views need to be animated or scrolled, <code>masksToBounds = YES</code> tax performance significantly, which means animation will probably get stuttered. To get rounded corner and shadow AND smooth animation or scrolling, use following code instead:</p> <pre><code>button.backgroundColor = [UIColor clearColor]; button.layer.backgroundColor = [UIColor redColor].CGColor; button.layer.masksToBounds = NO; button.layer.cornerRadius = 10.0f; view.layer.shadowOpacity = 0.5f; view.layer.shadowPath = [UIBezierPath bezierPathWithRoundedRect:_button.bounds cornerRadius:10.0f].CGPath; view.layer.shadowOffset = CGSizeMake(0.0f, 4.0f); view.layer.shadowRadius = 2.0f; view.layer.masksToBounds = NO; view.layer.cornerRadius = 10.0f; [view addSubview:button]; </code></pre>
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    1. POWhy masksToBounds = YES prevents CALayer shadow?
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    1. COThanks for the snippet, especially appreciate the shadowPath part...
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      1. USKendall Helmstetter Gelner
    2. CO+1 for the first answer. Your updated answer won't work for rounded corners.. If you set "masksToBounds" to "NO" then the rounded corners will disappear. Instead of changing that you can use "shouldRasterize" property to get the good performance.
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      1. USDinesh Raja
 

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