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PO
primarykey
Id
1558283
data
AcceptedAnswerId
0
AnswerCount
0
ClosedDate
CommentCount
0
CommunityOwnedDate
CreationDate
2009-10-13T05:05:35.317
FavoriteCount
0
LastActivityDate
2009-10-13T05:11:21.937
LastEditDate
2009-10-13T05:11:21.937
LastEditorUserId
87234
OwnerUserId
87234
ParentId
1558208
PostTypeId
2
Score
2
ViewCount
0
LastEditorDisplayName
text
Body
Although I'm a bit confused, because you're actual main code is missing. I'm going to assume you have a node, from traversing the link, and now want to print it: <pre><code>#include <iostream> #include <string> using namespace std; // not recommended, but useful // in snippets // T is usually used, but this is of course up to you template <class T> struct Node { typedef T value_type; // a usual typedef value_type info; Node<value_type> *next; }; struct Car { string maker; string year; string model; }; // you had a missing ;, probably copy-paste error // this creates a node. normally you'd want this to be // wrapped into a list class (more on this later) template <typename T> Node<T> *createNode(const T& info = T()) { // allocate node Node<T> *result = new Node<T>; result->info = info; result->next = 0; // no next return result; // returning a pointer means // whoever gets this is // responsible for deleting it! } // this is the output function for a node template <typename T> std::ostream& operator<<(std::ostream& sink, const Node<T>& node) { // note that we cannot assume what node contains! // rather, stream the info attached to the node // to the ostream: sink << node.info; return sink; } // this is the output function for a car std::ostream& operator<<(std::ostream& sink, const Car& car) { // print out car info sink << "Make: " << car.maker << "\nYear: " << car.year << "\nModel: " << car.model << std::endl; return sink; } int main(void) { // a car list typedef Node<Car> CarList; // a couple cars Car car1 = {"Dodge", "2001", "Stratus"}; Car car2 = {"GMan's Awesome Car Company", "The future", "The best"}; CarList *head = createNode(car1); // create the first node head->next = createNode(car2); // now traverse the list CarList *iter = head; for (; iter != 0; iter = iter->next) { // output, dereference iterator to get the actual node std::cout << "Car: " << *iter << std::endl; } // dont forget to delete! iter = head; while (iter) { // store next CarList *next = iter->next; // delete and move on delete iter; iter = next; } } </code></pre> Now, if you don't have to create your own linked list, use the standard link list instead, it simplifies your task immensely: <pre><code>#include <algorithm> #include <iostream> #include <iterator> #include <list> #include <string> using namespace std; struct Car { string maker; string year; string model; }; // this is the output function for a car std::ostream& operator<<(std::ostream& sink, const Car& car) { // print out car info sink << "Make: " << car.maker << "\nYear: " << car.year << "\nModel: " << car.model << std::endl; return sink; } int main(void) { // a car list typedef std::list<Car> CarList; // a couple cars Car car1 = {"Dodge", "2001", "Stratus"}; Car car2 = {"GMan's Awesome Car Company", "The future", "The best"}; CarList cars; cars.push_back(car1); cars.push_back(car2); // now traverse the list (copy to ostream) std::copy(cars.begin(), cars.end(), std::ostream_iterator<Car>(std::cout,"\n")); // delete done automatically in destructor } </code></pre> Hope this helps.
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1. This table or related slice is empty.
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1. POOperator Overload << in Linked List
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1. PTAnswer
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1. USGManNickG
UserOwnerUserId
1. USGManNickG
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2. VO
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