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POhow to pass location from jquery to php
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2013-03-22T11:54:17.487
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<p>This retrieves the map of the location:</p> <pre><code> <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/ 1.4.2/jquery.min.js"></script> <script type="text/javascript" src="jquery.cookie.js"></script> <script type="text/javascript"> function success(position) { var s = document.querySelector('#status'); if (s.className == 'success') { return; } s.innerHTML = "Found you!"; s.className = 'Success'; var mapcanvas = document.createElement('div'); mapcanvas.id = 'mapcanvas'; mapcanvas.style.height = '100%'; mapcanvas.style.width = '100%'; document.querySelector('#map').appendChild(mapcanvas); var latlng = new google.maps.LatLng(position.coords.latitude, position.coords.longitude); var myOptions = { zoom: 15, center: latlng, mapTypeControl: false, navigationControlOptions: {style: google.maps.NavigationControlStyle.SMALL}, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("mapcanvas"), myOptions); var marker = new google.maps.Marker({ position: latlng, map: map, title:"You are here!" }); $.cookie("MyLat", position.coords.latitude); // Storing latitude value $.cookie("MyLon", position.coords.longitude); // Storing longitude value } function error(msg) { var s = document.querySelector('#status'); s.innerHTML = typeof msg == 'string' ? msg : "failed"; s.className = 'Fail'; } if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(success, error); } else { error('Not supported'); //HTML Support } //Jquery Code $(document).ready(function() { $("#check").click(function() { var lat = $.cookie("MyLat"); var lon = $.cookie("MyLon"); alert('Latitued: '+lat); alert('Longitude: '+lon); var url="http://maps.googleapis.com/maps/api/geocode/json?latlng="+lat+","+lon+"&sensor=false"; alert('Google Map API: '+url); //Get Json Request Here }); }); </script> //HTML Code <input type='button' id='check' value='Check-out'/> <div id="status">Loading.............</div> <div id="map"></div> </code></pre> <p>I want to get only city and street address using GPS in jQuery and pass that city location to the PHP below, assigning the city address in php variable $city = //from jquery.</p> <p>And pass in $sql statement.</p> <pre><code>(i.e "select e.id, e.firstName, e.lastName, e.title, e.picture, count(r.id) reportCount " . "from employee e left join employee r on r.managerId = e.id " . "group by e.id order by e.lastName, e.firstName where e.city=$city";) <div data-role="content"> <ul data-role="listview" data-filter="true"> <?php include 'config.php'; $sql = "select e.id, e.firstName, e.lastName, e.title, e.picture, count(r.id) reportCount " . "from employee e left join employee r on r.managerId = e.id " . "group by e.id order by e.lastName, e.firstName"; try { $dbh = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $stmt = $dbh->query($sql); while ($emp = $stmt->fetch(PDO::FETCH_OBJ)) { echo "<li><a href='employeedetails.php?id=$emp->id'>" . "<img src='pics/$emp->picture'/>" . "<h4>$emp->firstName $emp->lastName</h4>" . "<p>$emp->title</p>" . "<span class='ui-li-count'>$emp->reportCount</span></a></li>"; } $dbh = null; } catch(PDOException $e) { echo $e->getMessage(); } ?> </ul> </div> </div> </code></pre> <p>Help me in getting this.</p>
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<php><jquery><html><sql>
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how to pass location from jquery to php
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1. CO[jQuery.ajax()](http://learn.jquery.com/ajax/) might be what you are looking for.
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  USAlex
2. CObut how to take street address using gps ??
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  POhow to pass location from jquery to php
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  USVicky V

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