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    <p>There is more to it.</p> <p><strong>1)</strong> For <strong>primitive</strong> or built-in types, <strong>implicitly</strong> initialized (or compiler initialized) means no-op (does nothing). </p> <p><strong>2)</strong> For <strong>primitive</strong> or built-in types, <strong>explicitly</strong> initialized (or initialized by the programmer) is obvious :) </p> <p>As in your example:</p> <pre><code> Student_info::Student_info(): midterm(0), final(0) {} </code></pre> <p><strong>3)</strong> For <strong>non-primitive</strong> types, <strong>implicitly</strong> initialized (or compiler initialized) means compiler may (or may not) synthesis a constructor for the purpose of initialization.</p> <blockquote> <pre><code> Usually, a constructor is synthesized by the compiler under the following cases: a) The non-primitive type is polymorphic or derives from some polymorphic/non-polymorphic types, b) The non-primitive type has a polymorphic/non-polymorphic member. Compiler synthesized constructor will usually have code to a) initialize v-pointer to v-table, b) call base class constructor, c) call constructors of members, so on, basically driven by the definition of non-primitive type. </code></pre> </blockquote> <p><strong>4)</strong> For <strong>non-primitive</strong> types, <strong>explicitly</strong> initialized (or initialized by the user supplied constructor) means compiler would make a call to the user defined constructor instead of synthesizing one for the purpose of initialization.</p> <p>For example, the default constructor defined by the respective non-primitive types (like std::string or std::vector) gets invoked. </p> <p>**</p> <blockquote> <p>Note: Compiler may still augment code inside the user-defined constructor to do some behind-the-scenes initialization as need be (look at step-3 above for such needs). Such augmented code will always be inserted before the user-defined code inside the constructor!</p> </blockquote> <p>**</p>
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    1. POConstructor initialization
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    1. COAlmost (very) good, but you are messing default construction ("compiler initialized") and the compiler generation of the def constr. Explicit initialization - you explicitaly call the constructor (no matter what exactly, can be the def constr, even one generated by compiler) and implicit or def const, the compiler call the def constr for you, no matter it is autom generated by compiler or user defined. Default constructor is simple the one without arg.
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    2. COHere is an extreme example of what Im trying to explain: http://stackoverflow.com/a/15416693/1458030
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    3. COSorry your comment is bit confusing. ""you are messing default construction ("compiler initialized")"" => Default construction is not always compiler initialized. That becomes evident when we supply a default constructor (the one without any parameter). The compiler is bound to call user defined default constructor whenever default construction happens.
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