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  1. PO
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    <p>Here's an alternative - if a component is found to contain less that 3 parts then parts are added at the start to take up the slack. It then uses a sort order array to define which columns should be compared next:</p> <pre><code> public void test() { String[] test = new String[]{ "alpha", "beta", "charlie", "zeta", // Added to demonstrate correctness. "sitea.alpha", "sitea.charlie", "sitea.pagea.beta", "sitea.pageb.beta", "sitea.pagea.charlie", "siteb.alpha", "siteb.delta", "siteb.pagef.alpha", "siteb.pageb.echo", "siteb.pageb.golf", "siteb.pagea.hotel", "siteb.pageb.hotel", "siteb.pagec.hotel" }; Arrays.sort(test); System.out.println("Normal sort: "+Arrays.toString(test)); Arrays.sort(test, new Comparator&lt;String&gt;() { // How many columns to pad to. final int padTo = 3; // What to pad with. final String padWith = ""; // What order to compare the resultant columns in. final int[] order = {0, 2, 1}; @Override public int compare(String s1, String s2) { String[] s1parts = padArray(s1.split(Pattern.quote(".")), padTo, padWith); String[] s2parts = padArray(s2.split(Pattern.quote(".")), padTo, padWith); int diff = 0; for ( int i = 0; diff == 0 &amp;&amp; i &lt; order.length; i++ ) { diff = s1parts[order[i]].compareTo(s2parts[order[i]]); } return diff; } String [] padArray(String[] array, int padTo, String padWith) { String [] padded = new String[padTo]; for ( int i = 0; i &lt; padded.length; i++ ) { padded[padded.length - i - 1] = i &lt; array.length ? array[i]: padWith; } return padded; } }); System.out.println("Special sort: "+Arrays.toString(test)); } </code></pre> <p>prints (more or less):</p> <pre><code>Normal sort: [alpha, beta, charlie, sitea.alpha, sitea.charlie, sitea.pagea.beta, sitea.pagea.charlie, sitea.pageb.beta, siteb.alpha, siteb.delta, siteb.pagea.hotel, siteb.pageb.echo, siteb.pageb.golf, siteb.pageb.hotel, siteb.pagec.hotel, siteb.pagef.alpha, zeta] Special sort: [alpha, beta, charlie, sitea.alpha, sitea.charlie, siteb.alpha, siteb.delta, zeta, siteb.pagef.alpha, sitea.pagea.beta, sitea.pageb.beta, sitea.pagea.charlie, siteb.pageb.echo, siteb.pageb.golf, siteb.pagea.hotel, siteb.pageb.hotel, siteb.pagec.hotel] </code></pre> <p>There does seem to be some ambiguity in your requirements but this code is structured so you can, with trivial tweaks, achieve most interpretations of your comparison quite simply.</p>
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    1. POSort algorithm problems on java comparable
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    1. USOldCurmudgeon
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    1. COdid you compare your output to OP's example output?
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    2. COYes - thus my "ambiguity" comment and the addition of the "zeta" value to demonstrate the ambiguities. Ahh!! I see OP wants site,key,page - I have given key, page, site. I will tweak.
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    3. COanyway, I got lost in OP's example output......
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