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    <p>You can't sort a <code>HashMap</code>, but you can sort its entries obtained with <code>entrySet()</code>.</p> <pre><code>public class MapSort { private static class Employee { public String name; public Employee(String name) { this.name = name; } @Override public String toString() { return name; } } public static void main(String[] args) { Map&lt;Integer, Employee&gt; map = new HashMap&lt;Integer, Employee&gt;(); map.put(1, new MapSort.Employee("x")); map.put(2, new MapSort.Employee("a")); map.put(3, new MapSort.Employee("f")); List&lt;Map.Entry&lt;Integer, Employee&gt;&gt; entryList = new ArrayList&lt;Map.Entry&lt;Integer, Employee&gt;&gt;(map.entrySet()); Collections.sort( entryList, new Comparator&lt;Map.Entry&lt;Integer, Employee&gt;&gt;() { @Override public int compare(Map.Entry&lt;Integer, Employee&gt; integerEmployeeEntry, Map.Entry&lt;Integer, Employee&gt; integerEmployeeEntry2) { return integerEmployeeEntry.getValue().name .compareTo(integerEmployeeEntry2.getValue().name); } } ); System.out.println(entryList); } } </code></pre> <p>After sorting you can put back your entries in a map that supports ordering, for example <a href="http://docs.oracle.com/javase/7/docs/api/java/util/LinkedHashMap.html" rel="nofollow">LinkedHashMap</a>. </p> <p>It depends on your use case: if you need to keep the map always sorted it's simpler to employ a <code>TreeMap</code> that comes with an additional overhead. If you need just an one time sorting, you can use a <code>HashMap</code> with the above code.</p>
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Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

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