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    <p>Here's another version of the code that is (hopefully) a bit more flexible. It finds the "(" sing, then ")", splits them with a comma, strips all the whitespace characters and converts the numbers into integers. Then it prints them out.</p> <pre><code>#include &lt;string&gt; #include &lt;iostream&gt; using namespace std; //these three functions are taken from here: //http://stackoverflow.com/questions/216823/whats-the-best-way-to-trim-stdstring #include &lt;algorithm&gt; #include &lt;functional&gt; #include &lt;cctype&gt; #include &lt;locale&gt; static inline std::string &amp;ltrim(std::string &amp;s) { s.erase(s.begin(), std::find_if(s.begin(), s.end(), std::not1(std::ptr_fun&lt;int, int&gt;(std::isspace)))); return s; } // trim from end static inline std::string &amp;rtrim(std::string &amp;s) { s.erase(std::find_if(s.rbegin(), s.rend(), std::not1(std::ptr_fun&lt;int, int&gt;(std::isspace))).base(), s.end()); return s; } // trim from both ends static inline std::string &amp;trim(std::string &amp;s) { return ltrim(rtrim(s)); } int main() { string s = "std::vector&lt;int&gt;(612,30)"; int paren_start = s.find("(")+1; string numbers = s.substr(paren_start, s.find(")")-paren_start); int comma_pos = numbers.find(","); string first_num = numbers.substr(0, comma_pos); string second_num = numbers.substr(comma_pos+1, numbers.size()-comma_pos); int first = atoi(trim(first_num).c_str()); int second = atoi(trim(second_num).c_str()); cout &lt;&lt; "{" &lt;&lt; endl; for(int i=0; i&lt;first; i++) { cout &lt;&lt; second &lt;&lt; " "; } cout &lt;&lt; "}" &lt;&lt; endl; return 0; } </code></pre>
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    1. COThis solution worked well in most of the situations except when the second number if float like std::vector<double>(6,0.0) I tried changing atoi to atof and 'second' variable to float but doesnt work. Any idea how to make it work thanks
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    2. COPerhaps you forgot to change int to double in "second" declaration?
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    3. COi got it ..thanks !
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