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POHow to print list according to index in Django template?
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I have a query like this in Django template: <pre><code> shared_username = [User.objects.filter(id__in= Share.objects.filter(users_id = log_id, files__file_name=k).values_list('shared_user_id', flat=True)).values_list('username') for k in file1] </code></pre> It gives the output like this: <pre><code>[[(u'fgdg',), (u'fsddfa',)], [(u'fgdg',)]] </code></pre> The first list <code>[(u'fgdg',), (u'fsddfa',)]</code> gives the shared_username of the first list and so on. I want to show the username for a file to the file. <pre><code>File Name Type Size Shared On Shared With </code></pre> In shared with I want to show the username for each file. I can loop the list twice or thrice and get all the username but like this I get all the user list for all files randomly. The output should be like: <pre><code> File Name Type Size Shared On Shared With ok.txt 2[link] hello.txt 1[link] ok1.txt 3[link] </code></pre> I am able to get the count of shared_with. When the user clicks on the link I want to show the usernames of the user with whom the file is shared. How can I achieve this? Thanks #models: <pre><code>class User(AbstractBaseUser): #id = models.IntegerField(primary_key=True) #identifier = models.CharField(max_length=40, unique=True, db_index=True) username = models.CharField(max_length=90, unique=True, db_index=True) create_time = models.DateTimeField(null=True, blank=True) update_time = models.DateTimeField(null=True, blank=True) email = models.CharField(max_length=225) #password = models.CharField(max_length=120) external = models.IntegerField(null=True, blank=True) deleted = models.IntegerField(null=True, blank=True) purged = models.IntegerField(null=True, blank=True) form_values_id = models.IntegerField(null=True, blank=True) disk_usage = models.DecimalField(null=True, max_digits=16, decimal_places=0, blank=True) objects = UserManager() USERNAME_FIELD = 'email' class Meta: db_table = u'galaxy_user' class File(models.Model): users = models.ForeignKey(User) file_name = models.CharField(max_length=100) type = models.CharField(max_length=10) source = models.CharField(max_length=100) start_date = models.TextField() time_overview = models.CharField(max_length=55) end_date = models.TextField() duration = models.TextField() size_overview = models.IntegerField() size = models.TextField() flag = models.TextField() flag_r = models.TextField() class Share(models.Model): users = models.ForeignKey(User) files = models.ForeignKey(File) shared_user_id = models.IntegerField() shared_date = models.TextField() </code></pre> <h1>views.py:</h1> <pre><code> log_id = request.user.id shared_file = File.objects.filter(id__in= Share.objects.filter(users_id = log_id).values_list('files', flat=True)).annotate(count=Count('share__shared_user_id')) file1 = [i.file_name for i in shared_file] shared_username = [User.objects.filter(id__in= Share.objects.filter(users_id = log_id, files__file_name=k).values_list('shared_user_id', flat=True)).values_list('username') for k in file1] </code></pre>
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How to print list according to index in Django template?
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