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POTrouble storing uploaded file into MySql
 

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  1. POTrouble storing uploaded file into MySql
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    <p>Hi I'm currently developing a quick prototype for my degree project. I have a previous form where users will select some options from dynamic dropdowns and when these have been saved into the tables the next page is for a user to upload a file. This file is then stored into a separate table with a foreign key referencing one other table. The problem is with the file upload page, I haven't included the the variable that represents the foreign key as i wanted to see if i could get it to work first. If anyone could help it would be much appreciated.</p> <p>The error i receive is either for the the name of the upload file not being a valid column name in the fields of the insert query or</p> <p>If I try to change the sql i get insert or update can not be done on a child table as the referential integrity is breached. </p> <p>Am I being thick? Ive been stuck for a few hours now.</p> <p>heres the php</p> <pre><code>if (isset($_POST['action']) and $_POST['action'] == 'upload') { $uploadfile = $_FILES['upload']['tmp_name']; $uploadname = $_FILES['upload']['name']; if(is_uploaded_file($uploadname)) { $uploadtype = $_FILES['upload']['type']; $uploaddata = file_get_contents($uploadfile); // Prepare user-submitted values for safe database insert $uploadname = mysql_real_escape_string($uploadname); $uploadtype = mysql_real_escape_string($uploadtype); $uploaddata = mysql_real_escape_string($uploaddata); $sql = "INSERT INTO product_logs (fileName, mimeType, fileData) VALUES (".$uploadname.",".$uploadtype.",".$uploaddata.")"; $exesql=mysql_query($sql) OR die(mysql_error()); } else { echo 'Error: File could not be uploaded.'; } } include("file.html.php"); </code></pre> <p>and here is the file.html.php</p> <pre><code>&lt;form action="" method="post" enctype="multipart/form-data"&gt; &lt;div&gt; &lt;label for="upload"&gt;Upload File: &lt;input type="file" id="upload" name="upload"/&gt;&lt;/label&gt; &lt;/div&gt; &lt;div&gt; &lt;input type="hidden" name="action" value="upload"/&gt; &lt;input type="submit" value="Upload"/&gt; &lt;/div&gt; &lt;/form&gt; </code></pre> <p>Here is the structure of the product_logs table</p> <pre><code>Field Type Null Key Default Extra logID int(5) NO PRI NULL auto_increment dateCreated date NO NULL malResultID int(6) NO MUL NULL mimeType varchar(50) NO NULL fileData mediumblob NO NULL fileName varchar(255) NO NULL </code></pre>
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    1. USDarryn Probert
    1. USDarryn Probert
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    1. COThanks everyone I managed to fix the problem.
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      1. USDarryn Probert
 

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