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POGet Data-dir value from jQuery and pass it to PHP
 

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    <p>I'm coping with a problem I can't figure out. </p> <p>I'm creating a menu for my website where I get all the values out of te database. I have four items: "Nintendo", "Playstation", "XBOX" and "PC". Each one of them has an unique ID. When one of the items are clicked on, I want to get that unique ID back. </p> <p>With this piece of code get my values printed out on my website: </p> <pre><code>echo "&lt;ul class=\"main_menu\"&gt;"; while($names = $get_category_names-&gt;fetch_object()) { echo "&lt;li data-dir=" . $names-&gt;id . "&gt;" . $names-&gt;name . "&lt;/li&gt;"; } echo "&lt;/ul&gt;"; </code></pre> <p>The part "li data-dir = names" is not working as expected. I console.log my values in jquery but I get the same ID back, which is 1. But, when I check Firebug, I see that I do get what I want, but this should probably be because HTML counts 4 li elements: </p> <pre><code>&lt;li data-dir="1"&gt;Nintendo&lt;/li&gt; &lt;li data-dir="2"&gt;Playstation&lt;/li&gt; &lt;li data-dir="3"&gt;Xbox&lt;/li&gt; &lt;li data-dir="4"&gt;PC&lt;/li&gt; </code></pre> <p>This is my jquery code:</p> <pre><code>$(document).ready(function() { var main_menu = $('ul.main_menu'); var sub_menu = $('ul.sub_menu'); sub_menu.hide(); var find_li = main_menu.find('li'); main_menu.on('click', function() { //sub_menu.fadeIn(200); find_li.data('dir'); console.log(find_li.data('dir')); }) }); </code></pre> <p>Can anybody point me to the right direction?</p> <p>Thanks a bunch. </p> <p>Edit: The solution to this question is below. I did not understand my code good enough to look at the right places. </p>
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