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Here's a hacky solution with some extra typing, but without backticks! I first posted this on reddit, if that's okay. I assume you have derived <code>Enum</code> for <code>Rank</code>. <pre><code>data OF = OF ace :: OF -> Suit -> PokerCard ace _ s = PokerCard Ace s -- or point-free two :: OF -> Suit -> PokerCard two _ = PokerCard Two -- or with const three :: OF -> Suit -> PokerCard three = const (PokerCard Three) -- you get the idea! -- the rest in one line: four,five,six,seven,eight,nine,ten,jack,king :: OF -> Suit -> PokerCard [four,five,six,seven,eight,nine,ten,jack,king] = map (const . PokerCard) [Four .. King] -- now you can write pokerDeck = [ ace OF Spades, two OF Spades -- and so on ] </code></pre> The OF datatype isn't strictly necessary, but prevents confusing (but very metal) stuff like <code>ace "Motorhead" Spades</code>. You can still write <code>ace undefined Spades</code>, there's really no way around that, I think. If <code>of</code> wasn't a keyword, you could even write <code>of = OF</code>. <hr> There is also an utterly evil hack to get rid of the 'of' entirely, and using numbers for cards: <pre><code>{-# LANGUAGE FlexibleInstances #-} -- this goes on top of your file instance Num (Rank -> Suit) where fromInteger n = (undefined : map Card[Ace .. King]) !! (fromInteger n) </code></pre> Now <code>2 Spades :: Card</code> typechecks (but you need the explicit type!) and is what you think it is :-) However, I strongly advise you to not do this in serious code; but it looks kind of cool.
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1. POHow do I define infix functions in Haskell?
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1. USyatima2975
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