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POHow to have virtual functions that returns different types based on the class to which it belongs without including dummy implementation in Base?
 

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  1. POHow to have virtual functions that returns different types based on the class to which it belongs without including dummy implementation in Base?
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    <p>I need a class hierarchy in which the derived classes will have implementation of a virtual function that differs in the return type. How can i do it. What i have tried is the following code:</p> <pre><code>using namespace std; class Base { public: Base() { cout&lt;&lt;"Constructor of Base"&lt;&lt;endl; } virtual Base&amp; Decode()=0; virtual operator int(){return -1;} virtual operator string(){return "WRONG";} }; class Der1:public Base { int i; public: Der1(int j=0):Base(),i(j) { cout&lt;&lt;"COnstructor of Der1"&lt;&lt;endl; } Base&amp; Decode() { cout&lt;&lt;"Decode in Der1"&lt;&lt;endl; return *this; } operator int() { return i; } }; class Der2:public Base { string s; public: Der2(string temp="sajas"):Base(),s(temp) { cout&lt;&lt;"Constructor of Der2"&lt;&lt;endl; } Base&amp; Decode() { cout&lt;&lt;"Decode in Der2"&lt;&lt;endl; return *this; } operator string() { return s; } }; int main() { Base *p=new Der1(); int val=p-&gt;Decode(); } </code></pre> <p>I was thinking if it could work this way user would just have to equate the object to a valid variable. Is there any way to do it without including all the conversion operators in Base with some dummy implementatin?</p>
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    1. COGood question :)
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      1. USNirmalGeo
 

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