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    <p>I think using PhantomJS will be the easiest. No need for node.js.</p> <p>You can combine <code>examples/scandir.js</code> and <code>examples/phantomwebintro.js</code> to get what you want.</p> <pre><code>var system = require('system'); var fs = require('fs'); if (system.args.length !== 2) { console.log("Usage: phantomjs scandir.js DIRECTORY_TO_SCAN"); phantom.exit(1); } function scanDirectory(path, cb) { if (fs.exists(path) &amp;&amp; fs.isFile(path)) { cb(path); } else if (fs.isDirectory(path)) { fs.list(path).forEach(function (e) { if (e !== "." &amp;&amp; e !== "..") { scanDirectory(path + '/' + e, cb); } }); } } function parsePage(path) { var page = require('webpage').create(); page.open(path, function(status) { if (status === "success") { page.includeJs("http://code.jquery.com/jquery-latest.js", function() { var images = page.evaluate(function() { var images = []; $('img').each(function() { images.push({ src: $(this).attr('src'), pos: $(this).position() }); }); return images; }); console.log(images); }); } }); } scanDirectory(system.args[1], parsePage); </code></pre> <p>This script (<code>phantomjs img.js kittens</code>) will scan the directory for files, load every file in that directory (and subdirectories, you can modify this behavior in <code>scanDirectory</code>) and find all <code>&lt;img&gt;</code> tags on that page and return an array with their <code>src</code> attributes and <code>.position()</code>.</p> <p>Took me about 20 minutes to get this to work, so I think this is the easiest way.</p>
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Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

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