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POIndexing an std::vector with a negative index
 

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  1. POIndexing an std::vector with a negative index
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    <p>I tried to index a <code>vector</code> using a negative index. The <code>vector::at()</code> member function checks whether the specified index is within the bounds of the vector, and if this does not occur, an <code>out_of_range</code> exception is thrown.</p> <pre><code>vector&lt;float&gt; array; // sample vector array.push_back(0.123); array.push_back(1.234); array.push_back(2.345); array.push_back(3.456); array.push_back(4.567); int index = -1; float f = array.at(index); cout &lt;&lt; f &lt;&lt; endl; </code></pre> <p>The signature of <code>vector::at()</code> member function requires that the specified parameter is of <code>vector&lt;T&gt;::size_type</code> type, and this type is <code>unsigned int</code> for the vector, so the compiler should perform an implicit conversion from <code>int</code> (the type of the <code>index</code> variable) to <code>unsigned int</code>. Since the <code>index</code> value is <code>-1</code> in the above example, the implicitly converted <code>index</code> is <code>4294967295</code> (that is the max value of the <code>unsigned int</code> type): this value is passed to <code>vector::at()</code> member function, which throws an <code>out_of_range</code> exception.</p> <p>In other words, this exception is not thrown because the <code>vector::at()</code> member function sees that the <code>index</code> is less than zero, but rather because the implicitly converted <code>index</code> is greater than the current size of the <code>vector</code>. Is this a correct explanation?</p>
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    1. USenzom83
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      1. VTUpMod
    1. COYes, basically.
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      1. USDave
    2. COYes, that is the right explanation.
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      1. USsyam
 

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