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  1. PO
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    <p>If I try your codes, neither does any replacement, because there is no semicolon after the value that you are trying to replace.</p> <p>If you remove the semicolon from the regular expression, both works:</p> <pre><code>html = Regex.Replace(html, @"(['""#(=])" + "oldvalue" + @"(['""#)]|&amp;)", "$1" + "asdf" + "$2", RegexOptions.IgnoreCase); </code></pre> <p>does the same as:</p> <pre><code>var regex = new Regex(@"(['""#(=])" + "oldvalue" + @"(['""#)]|&amp;)", RegexOptions.IgnoreCase); foreach (Match match in regex.Matches(html)) { html = html.Replace(match.Value, match.Groups[1] + "asdf" + match.Groups[2]); } </code></pre> <h3>Edit:</h3> <p>When I try the updated code from the question, it works fine:</p> <pre><code>string html; KeyValuePair&lt;string, string&gt; elementReference = new KeyValuePair&lt;string, string&gt;("oldvalue", "newvalue"); html = "&lt;td&gt;[element]elementreference='oldvalue';[/element]&lt;/td&gt;"; html = Regex.Replace(html, @"(['""#(=])" + elementReference.Key + @"(['""#)];|&amp;)", "$1" + elementReference.Value + "$2", RegexOptions.IgnoreCase); Console.WriteLine(html); html = "&lt;td&gt;[element]elementreference='oldvalue';[/element]&lt;/td&gt;"; var regex = new Regex(@"(['""#(=])" + elementReference.Key + @"(['""#)];|&amp;)", RegexOptions.IgnoreCase); foreach (Match match in regex.Matches(html)) { html = html.Replace(match.Value, match.Groups[1] + elementReference.Value + match.Groups[2]); } Console.WriteLine(html); </code></pre> <p>Output:</p> <pre><code>&lt;td&gt;[element]elementreference='newvalue';[/element]&lt;/td&gt; &lt;td&gt;[element]elementreference='newvalue';[/element]&lt;/td&gt; </code></pre>
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    1. PORegex back references in Regex.Replace()
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    1. USGuffa
    1. USGuffa
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    1. PORegex back references in Regex.Replace()
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    1. COI missed the semi-colon when editing the line in my question. The regex needs the semi-colon
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      1. USLisa Young
    2. CO@LisaYoung: If you add the semicolon in the original value, then the code works just fine as it is.
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      1. USGuffa
    3. COEvery time I've run the code, using Regex.Replace() the output does contains $1 instead of the back reference.
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      1. USLisa Young
 

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