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    <p>This seems to work for me (writes decoded string to the console):</p> <pre><code>data = "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"; key = "2e35f242a46d67eeb74aabc37d5e5d05"; // Decode the base64 data so we can separate iv and crypt text. var rawData = atob(data); var iv = btoa(rawData.substring(0,16)); var crypttext = btoa(rawData.substring(16)); // Decrypt... var plaintextArray = CryptoJS.AES.decrypt( { ciphertext: CryptoJS.enc.Base64.parse(crypttext), salt: "" }, CryptoJS.enc.Hex.parse(key), { iv: CryptoJS.enc.Base64.parse(iv) } ); // Convert hex string to ASCII. // See https://stackoverflow.com/questions/11889329/word-array-to-string function hex2a(hex) { var str = ''; for (var i = 0; i &lt; hex.length; i += 2) str += String.fromCharCode(parseInt(hex.substr(i, 2), 16)); return str; } console.log(hex2a(plaintextArray.toString())); </code></pre> <p>The important bits are to specify no salt in your input and pass the key as a WordArray as jlvaquero says. There are probably some efficiency improvements to be made, e.g. I'm guessing there's an easier way to convert a string to a WordArray than going to base64 and back, but at least it successfully decodes. I lifted the hex2a function from StackOverflow question <a href="https://stackoverflow.com/questions/11889329/word-array-to-string">Word Array to String</a>.</p> <p>Edit: I figured out how to convert strings to WordArrays and vice-versa with CryptoJS so the extra base64 encode/decode and hex-to-ASCII function are not needed. Also it turns out the salt property need not be specified. This is more compact and efficient:</p> <pre><code>data = "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"; key = "2e35f242a46d67eeb74aabc37d5e5d05"; // Decode the base64 data so we can separate iv and crypt text. var rawData = atob(data); var iv = rawData.substring(0,16); var crypttext = rawData.substring(16); // Decrypt... var plaintextArray = CryptoJS.AES.decrypt( { ciphertext: CryptoJS.enc.Latin1.parse(crypttext) }, CryptoJS.enc.Hex.parse(key), { iv: CryptoJS.enc.Latin1.parse(iv) } ); console.log(CryptoJS.enc.Latin1.stringify(plaintextArray)); </code></pre>
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    1. COI confirm this succeeds. He/she should get the bounty. Thanks!
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    2. COWell done :) Thanks!
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