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The form of the function that you're using (<code>hist(data,1000)</code>) means that 1000 bins are generated, and MATLAB is defaulting to sizing them with a width of 1 because it has no information about the range of the data (a single value doesn't have a meaningful range). Here's a blurb from the <a href="http://www.mathworks.com/help/matlab/ref/hist.html" rel="nofollow">documentation</a>: <blockquote> n = hist(Y,nbins) where nbins is a scalar, uses nbins number of bins. </blockquote> There are a few options that could make it "better" (in quotes, because nobody but you knows what you want): 1) You could use a different form of the function to specify where the bins should be: <blockquote> n = hist(Y,x) where x is a vector, returns the distribution of Y among length(x) bins with centers specified by x. For example, if x is a 5-element vector, hist distributes the elements of Y into five bins centered on the x-axis at the elements in x, none of which can be complex. Note: use histc if it is more natural to specify bin edges instead of centers. </blockquote> 2) You could limit the number of bins to the number of elements in the data vector, if less than some minimum value: <pre><code>hist(data, min(1000, numel(data))) </code></pre> 3) You could check for special cases (like N=1) - you mention that this is not desirable, but using a script/function this isn't a hardship at all, so you may have to clarify why this isn't acceptable. 4) You could scale the x-axis appropriately after plotting (similar to @Parag's answer)
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