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POPython regular expression for r.findall
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15098789
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2013-02-26T20:38:02.783
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2013-02-26T21:46:56.573
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2013-02-26T20:43:17.150
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Body
I am using findall to separate text. I started with this expression re.findall(r'(.?)(\$.?\$)' but it doesn't give me the data after the last piece of text found. I missed the '6\n\n' How do I get the last piece of text? Here is my python code: <pre><code>#!/usr/bin/env python import re allData = ''' 1 2 3 here Some text in here $file1.txt$ 4 Some text in here and more $file2.txt$ 5 Some text $file3.txt$ here $file3.txt$ 6 ''' for record in re.findall(r'(.*?)(\$.*?\$)|(.*?$)',allData,flags=re.DOTALL) : print repr(record) </code></pre> The output I get for this is: <pre><code>('\n1\n2\n3 here Some text in here \n', '$file1.txt$', '') ('\n4 Some text in here and more ', '$file2.txt$', '') ('\n5 Some text ', '$file3.txt$', '') (' here \n', '$file3.txt$', '') ('', '', '\n6\n') ('', '', '') ('', '', '') </code></pre> I really would like this output: <pre><code>('\n1\n2\n3 here Some text in here \n', '$file1.txt$') ('\n4 Some text in here and more ', '$file2.txt$') ('\n5 Some text ', '$file3.txt$') (' here \n', '$file3.txt$') ('\n6\n', '', ) </code></pre> <hr> Background info in case you need to see the larger picture. I case your are interested, I'm re-writing this in python. I have the rest of the code under control. I am just getting too much stuff out of findall. <a href="https://discussions.apple.com/message/21202021#21202021" rel="nofollow">https://discussions.apple.com/message/21202021#21202021</a>
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<python><regex>
Title
Python regular expression for r.findall
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 POPython regular expression for r.findall
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