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15098032
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2013-02-26T19:52:49.947
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2013-02-26T19:52:49.947
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The solution in this case was to create the temporary output buffer using <code>with-temp-buffer</code>, rather than explicitly creating one with <code>generate-new-buffer</code>. The following alternative version of the first function does not create an undo boundary: <pre><code>(defun test-shell-command (str) "Apply tr to STR to convert lowercase letters to uppercase." (with-temp-buffer (insert str) (call-process-region (point-min) (point-max) "tr" t t nil "'a-z'" "'A-Z'") (buffer-string))) </code></pre> I was not able to determine whether <code>generate-new-buffer</code> is indeed creating the undo boundary, but this fixed the problem. <code>generate-new-buffer</code> calls <code>get-buffer-create</code>, which is defined in the C source code, but I could not quickly determine what was happening in terms of the undo history. I suspect that the issue may be related to the following passage in the <a href="http://www.gnu.org/software/emacs/manual/html_node/elisp/Undo.html" rel="nofollow">Emacs Lisp Manual entry for <code>undo-boundary</code></a>: <blockquote> All buffer modifications add a boundary whenever the previous undoable change was made in some other buffer. This is to ensure that each command makes a boundary in each buffer where it makes changes. </blockquote> Even though the <code>with-temp-buffer</code> macro calls <code>generate-new-buffer</code> much as in the original function, the documentation for <code>with-temp-buffer</code> states that no undo information is saved (even though there is nothing in the Emacs Lisp source that suggests this would be the case): <blockquote> By default, undo (see Undo) is not recorded in the buffer created by this macro (but body can enable that, if needed). </blockquote>
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1. POHow to prevent Emacs from setting an undo boundary?
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1. USJason Blevins
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