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    <p>From <strong><a href="http://msdn.microsoft.com/en-us/library/ey1471zb%28v=vs.90%29.aspx" rel="nofollow">Compiler Error CS1517</a></strong></p> <p>The following sample shows some valid and invalid preprocessor expressions:</p> <pre><code>#if symbol // OK #endif #if !symbol // OK #endif #if (symbol) // OK #endif #if true // OK #endif #if false // OK #endif #if 1 // CS1517 #endif #if ~symbol // CS1517 #endif #if * // CS1517 #endif class x { public static void Main() { } } </code></pre> <p>So I think you can use like this;</p> <pre><code>#define _MyType #If _MyType </code></pre> <p>From <strong><a href="http://msdn.microsoft.com/en-us/library/4y6tbswk%28v=vs.90%29.aspx" rel="nofollow">#if</a></strong> </p> <blockquote> <p>When the C# compiler encounters an #if directive, followed eventually by an #endif directive, it will compile the code between the directives <strong>only if the specified symbol is defined</strong>. Unlike C and C++, you cannot assign a numeric value to a symbol; the #if statement in C# is Boolean and only tests whether the symbol has been defined or not.</p> </blockquote> <pre><code>#define DEBUG // ... #if DEBUG Console.WriteLine("Debug version"); #endif </code></pre> <blockquote> <p><strong>You can use the operators == (equality), != (inequality) only to test for true or false . True means the symbol is defined</strong>. The statement -#if DEBUG has the same meaning as #if (DEBUG == true). The operators &amp;&amp; (and), and || > (or) can be used to evaluate whether multiple symbols have been defined. You can also group symbols and operators with parentheses.</p> </blockquote>
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    1. USSoner Gönül
    1. USSoner Gönül
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    1. COSoner if a pre-processor directive then he would need the `#` otherwise why use it in the first place..??
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    2. CO-1 You cannot just change a preprocessor directive to a regular if statement and expect it to work.
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      1. USjuharr
    3. CO@DJKRAZE and juharr, Thanks guys. You are right! Updated my answer.
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