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    <p><strong>Edit:</strong></p> <p>Assuming the array you've updated to is called $table:</p> <pre><code>// $S is array for S where sums are stored $S = array(); $S[0] = $table[0][v] - $table[0][p]; // Perform the first row for ($i=1; $i&lt; count($table); $i++) { // Start at 2nd and continue on $S[$i] = $S[($i-1)] + ($table[$i][v] - $table[$i][p]); } </code></pre> <p>Now all the $S values are populated as such. If you want to add to the table:</p> <pre><code>$table[0][s] = $table[0][v] - $table[0][p]; // Perform the first row for ($i=1; $i&lt; count($table); $i++) { // Start at 2nd and continue on $table[$i][s] = $table[$i-1][s] + ($table[$i][v] - $table[$i][p]); } </code></pre> <hr> <p>Yes you can, considering you want the S values of 1, 2, 3 ... then yes. I assume V is an array and P is an array so you'll have to change accordingly, since each S can be based off the previous, I keep a running_sum value so that we don't have to iterate over previous values of V and P, we just use the last value of S:</p> <pre><code>// $V is array for V and $P is array for P and // $S is array for S where sums are stored if (count($V) == count($P)) { // Check both V and P are same length $running_sum = 0; for ($i=0; $i&lt; count($V); $i++) { $running_sum += ($V[$i] - $P[$i]); $S[$i] = $running_sum; } } </code></pre> <p>We really don't need the running sum variable though but I used it to make the logic clear, here it is without it:</p> <pre><code>// $V is array for V and $P is array for P and // $S is array for S where sums are stored if (count($V) == count($P)) { // Check both V and P are same length $S[0] = $V[0] - $P[0]; // Perform the first row for ($i=1; $i&lt; count($V); $i++) { // Start at 2nd and continue on $S[$i] = $S[($i-1)] + ($V[$i] - $P[$i]); } } </code></pre>
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    1. POComputing the sum of values after a give algorithm
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    1. COI have updated the post with the array example.
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    2. COIn the first code block, in the for loop, doesn't it have to be ($table[$i][v] - $table[$i][p]) instead of ($table[0][v] - $table[0][p]) ?
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    3. COYes, you're correct, sorry I copy pasted incorrectly.
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